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nata0808 [166]
3 years ago
15

What is used to connect computers to the internet*Audio Ports

Computers and Technology
2 answers:
Andrews [41]3 years ago
4 0

Answer: it is HDMI, you had it on the list already

SOVA2 [1]3 years ago
3 0

Answer:

The person on top is wrong, the first one is VGA PORT not HDMI PORT.

and the second one is HDMI PORT

Explanation:

You might be interested in
For which of the four game elements will you give a detailed description about the challenges that the player will face, such as
vaieri [72.5K]

The four game elements that will give you  a detailed description about the challenges that the player will face is option D: objective.

<h3>What goals does game development have?</h3>

To bring about creativity and originality in task completion and issue solving. to prepare pupils for group collaboration.

Note that giving the player a clear objective gives them something to aim for. Make sure the player can relate to this motivation.

Therefore, The most crucial component of a game can be its objectives, which determine how the game is won or lost, what the player is instructed to perform in-game, and what the player must do to gain optional <em>Achievements</em>.

Learn more about objective from

brainly.com/question/18516671
#SPJ1

3 0
1 year ago
"Write an iterative function iterPower(base, exp) that calculates the exponential baseexp by simply using successive multiplicat
sp2606 [1]

Answer:

I am writing the function using Python. Let me know if you want the program in some other programming language.            

def iterPower(base, exp):    

    baseexp = 1

    while exp > 0:

        baseexp = baseexp*base

        exp= exp - 1

    return baseexp

base = 3

exp = 2

print(iterPower(base, exp))

Explanation:

  • The function name is iterPower which takes two parameters base and exp. base variable here is the number which is being multiplied and this number is multiplied exponential times which is specified in exp variable.
  • baseexp is a variable that stores the result and then returns the result of successive multiplication.
  • while loop body keeps executing until the value of exp is greater than 0. So it will keep doing successive multiplication of the base, exp times until value of exp becomes 0.
  • The baseexp keeps storing the multiplication of the base and exp keeps decrements by 1 at each iteration until it becomes 0 which will break the loop and the result of successive multiplication stored in baseexp will be displayed in the output.
  • Here we gave the value of 3 to base and 2 to exp and then print(iterPower(base, exp)) statement calls the iterPower function which calculates the exponential of these given values.
  • Lets see how each iteration works:
  • 1st iteration

baseexp = 1

exp>0 True because exp=2 which is greater than 0

baseexp = baseexp*base

               = 1*3 = 3

So baseexp = 3

exp = exp - 1

      = 2 - 1 = 1    

exp = 1

  • 2nd iteration

baseexp = 3

exp>0 True because exp=1 which is greater than 0

baseexp = baseexp*base

               = 3*3 = 9

So baseexp = 9

exp = exp - 1

      = 1-1 = 0    

exp = 0

  • Here the loop will break now when it reaches third iteration because value of exp is 0 and the loop condition evaluates to false now.
  • return baseexp statement will return the value stored in baseexp which is 9
  • So the output of the above program is 9.
5 0
3 years ago
Use the single-server drive-up bank teller operation referred to in Problems 1 and 2 to determine the following operating charac
elena-s [515]

Answer:

This question is incomplete, here's the complete question:

1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute. 3. Use the single-server drive-up bank teller operation referred to in Problems 1 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Explanation:

Arrival rate \lambda = 24 customers per hour or 0.4 customers per minute

Service rate \mu​ = 36 customers per hour or 0.6 customers per minute (from problem 1)

a.) The probability that no customers are in the system , P0 = 1 - \lambda / \mu

= 1 - (24/36) = 1/3 = 0.3333

b.) The average number of customers waiting

Lq = \lambda^2 / [\mu(\mu - \lambda)] = 242 / [36 * (36 - 24)] = 1.33

c.) The average number of customers in the system.

L = Lq + \lambda / \mu = 1.33 + (24/36) = 2

d.) The average time a customer spends waiting.

Wq = \lambda / [\mu(\mu - \lambda)] = 24 / [36 * (36 - 24)] = 0.0555 hr = 3.33 min

e.) The average time a customer spends in the system

W = Wq + 1/\mu = 0.0555 + (1/36) = 0.0833 hr = 5 min

f.) The probability that arriving customers will have to wait for service.

= 1 - P0 = 1 - 0.3333 = 0.6667

3 0
3 years ago
patty works at Mcdonald's as a chef. it is her job to make hamburgers as each order arrives on her computer screen. one day patt
il63 [147K]
Angela should make sure the hamburger patty is disposed of and a new one prepared for the hamburger. She should reprimand Patty as what she did is wrong. Patty could well be fired for what she did. It is unsafe and unsanitary to give a customer food that has fallen on the floor. Angela should make sure this never happens again.

4 0
3 years ago
Read 2 more answers
Outputting all combinations. Output all combinations of character variables a, b, and c using this ordering abc acb bac bca cab
Alina [70]

Answer:

#include<iostream>

using namespace std;

 

int main()

{

   char a;  

   char b;  

   char c;

cin >> a;  

cin >> b;  

cin >> c;

 cout<<a<<b<<c<<endl;

 cout<<a<<c<<b<<endl;

 cout<<b<<a<<c<<endl;

 cout<<b<<c<<a<<endl;

 cout<<c<<a<<b<<endl;

 cout<<c<<b<<a<<endl;

 

cout << endl;

}

Explanation:

Note: code is hard coded it does not contain any logic based coding

5 0
3 years ago
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