All categories

3 years ago

Calculate the mean, median and mode of the following data.

Mathematics

2 answers:

nika2105 [10]3 years ago

8 0

The correct answer to this is D I forgot how to do this but I remember what mean median and mode are

garik1379 [7]3 years ago

3 0

Answer:

d.mean =15, median =15.5, mode = 16

Step-by-step explanation:

hello,

to find the mean, you add all the numbers together and divide it by the total number of numbers. so that would be 150 (total sum) divided by 10 (number of numbers) to get 15.

to find the median, you would organize the numbers from least to greatest and find the middle number which is 15.5.

last but not least, to find the mode, just look for the number that appears most often. Therefore, the mode would be 16.

hope this helped!

You might be interested in

In 2016, the mean score on the AP Art History exam was 3.8, with a standard deviation of 1.2. The mean score on the AP English e

Ulleksa [173]

Answer:

$X+Y \sim N(\mu_X +\mu_Y , \sqrt{\sigma^2_X +\sigma^2_Y})$

The mean is given by:

$\mu = 3.8+2.9= 6.7$

And the standard deviation would be:

$\sigma =\sqrt{1.2^2 + 1.7^2} = 2.08$

And the distribution for X+Y would be:

$X+Y \sim N(6.7 , 2.08)$

And the best answer would be:

D.) Mean, 6.7; standard deviation, 2.08

Step-by-step explanation:

Let X the random variable who represent the AP Art History exam we know that the distribution for X is given by:

$X \sim N(3.8, 1.2)$

Let Y the random variable who represent the AP English exam we know that the distribution for X is given by:

$X \sim N(2.9, 1.7)$

We want to find the distribution for X+Y. Assuming independence between the two distributions we have:

$X+Y \sim N(\mu_X +\mu_Y , \sqrt{\sigma^2_X +\sigma^2_Y})$

The mean is given by:

$\mu = 3.8+2.9= 6.7$

And the standard deviation would be:

$\sigma =\sqrt{1.2^2 + 1.7^2} = 2.08$

And the distribution for X+Y would be:

$X+Y \sim N(6.7 , 2.08)$

And the best answer would be:

D.) Mean, 6.7; standard deviation, 2.08

8 0

3 years ago

Read 2 more answers

(x-1)(x+20)<br> May I know the work to this

nikitadnepr [17]

$(x-1)(x+20)=x^2+20x-x-20=x^2+19x-20$

4 0

4 years ago

Read 2 more answers

In a class of 27 students, 7 have a cat and 9 have a dog. There are 5 students who have a cat and a dog. What is the probability

Lelechka [254]

Answer: 5/7

Step-by-step explanation: 27 and 9 are both irrelevant numbers.

If we see here, it is given that they have a cat. 7 people have a cat! And because those 5 students who have both are listed under both categories, there are 5 students in the 7! Therefore, 5/7 is the desired probability...

4 0

3 years ago

Which equation describes the pattern of the data in the table?

slega [8]

Answer:

Option A. y = 4x

Step-by-step explanation:

From the question given above, the following data were obtained:

X >> Y

3 >> 12

4 >> 16

5 >> 20

6 >> 24

7 >> 28

Next, we shall use each of the options to obtain the first two value of y to which will correspond to the table above. This is illustrated below:

For Option A:

1. y = 4x

x = 3

y = 4 × 3

y = 12

2. y = 4x

x = 4

y = 4 × 4

y = 16

For Option B:

1. y = 4x + 12

x = 3

y = 4(3) + 12

y = 12 + 12

y = 24

2. y = 4x + 12

x = 4

y = 4(4) + 12

y = 16 + 12

y = 28

For Option C:

1. y = ¼ x

x = 3

y = ¼ × 3

y = ¾

2. y = ¼ x

x = 4

y = ¼ × 4

y = 1

For Option D:

1. y = ¼x + 12

x = 3

y = ¼(3) + 12

y = ¾ + 12

y = 51/4

2. y = ¼x + 12

x = 4

y = ¼(4) + 12

y = 1 + 12

y = 13

From the calculations made above, only option A ie. y = 4x correspond to the data given in the table above.

5 0

3 years ago

Betty is canning 104 pears and 126 apples separately. Each jar holds 8 pears or 6 apples. How many jars does Betty need

Nina [5.8K]

For the pears, Betty will need 13 jars. I know this because I divided 104 by 8. I did the same for the apples. 126 divided by 6. You get 21. Have a nice day!

8 0

4 years ago