Answer:
x=-2 and -32/3
Step-by-step explanation:
|3x+19|=13
3x+19=13 and 3x+19=-13
x=-2 and x=-32/3
Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
La respuesta es 112, es una regla de tres simples
I think you mean 8x^2 + 7 =0
a = 8 b = 0 c = 7
x= [-b +- square root (b^2 - 4*a*c)] / 2a
x = [0 +- square root (0 - 4*8*7)] / 2*8
x = +- square root (-224) / 16
x = +-
<span>
<span>
<span>
14.9666295471 * i
</span>
</span>
</span>
/ 16
x = +
<span>
<span>
<span>
0.9354143467
</span>
</span>
</span>
i
x = -
<span>
<span>
0.9354143467
</span>
</span>
i