Ask question

Ask question

All categories

3 years ago

9

A 20.00-mL sample of a weak base is titrated with 0.0568 M HCl. At the endpoint, it is found that 17.88 mL of titrant was used.

What was the concentration of the weak base?

1 answer:

nata0808 [166]3 years ago

7 0

Answer: 0.0508mL

Explanation: Using the basic formula that states: C acid * V acid = C base * V base. we have:0.568 * 17.88 = 20 * C base.

therefore concentration of the base is 1.0156/20 = 0.0508 mL

You might be interested in

A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reacta

melomori [17]

Cao + H2O ---->Ca(OH)2
Calculate the number of each reactant and the moles of the product
that is
moles = mass/molar mass
The moles of CaO= 56.08g/ 56.08g/mol(molar mass of Cao)= 1mole
the moles of water= 36.04 g/18 g/mol= 2.002moles
The moles of Ca (OH)2=74.10g/74.093g/mol= 1mole

The mass of differences of reactant and product can be therefore
explained as
1 mole of Cao reacted completely with 1 mole H2O to produce 1 mole of Ca(OH)2. The mass of water was in excess while that of CaO was limited

3 0

3 years ago

What is the total mass of Hydrogen in each of the molecules?

frutty [35]

Explanation:

a) In 1 mole of methane there are 4 moles of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of methane = 4 × 1 g = 4 g

b) In 1 mole of chloroform there are 1 mole of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of methane = 1× 1 g = 1 g

c) In 1 mole of $C_{12}H_{10}O_{16}$ there are 10 moles of hydrogen atom

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of $C_{12}H_{10}O_{16}$ = 10 × 1 g = 10 g

d)In 1 mole of $CH_3CH_2CH_2CH_2CH_3$ there are 12 moles of hydrogen atom.

$CH_3CH_2CH_2CH_2CH_3=C_5H_{12}$

Atomic mass of 1 mole of hydrogen atom = 1 g

Mass of hydrogen in 1 mole of $CH_3CH_2CH_2CH_2CH_3$ = 12 × 1 g = 12 g

3 0

4 years ago

Can somebody please help me ?

larisa [96]

Answer:

I belive it is either a element or co mpound Hope this helped :D :3

Explanation:

4 0

3 years ago

Find the formula for the compound that contains 72.40% iron and 27.60% oxygen.

Vikki [24]

Oxygen = 16
Iron = 55.8
16 x 27.6% = 4.4 /4 = 1.1
55.8 x 72.4% = 40.4 /4 = 10.1
1 oxygen and 10 iron, so Fe10 O

8 0

4 years ago

Give an example of competition in an ecosystem

neonofarm [45]

hbzjaj

Explanation:

competition for food

5 0

3 years ago