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VMariaS [17]
3 years ago
9

A 20.00-mL sample of a weak base is titrated with 0.0568 M HCl. At the endpoint, it is found that 17.88 mL of titrant was used.

What was the concentration of the weak base?
Chemistry
1 answer:
nata0808 [166]3 years ago
7 0

Answer: 0.0508mL

Explanation: Using the basic formula that states: C acid * V acid = C base * V base. we have:0.568 * 17.88 = 20 * C base.

therefore concentration of the base is 1.0156/20 = 0.0508 mL

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natural rubidium has the average mass of 85.4678 and is composed of isotopes 85 Rb(mass = 84.9117) and 87 Rb. The ratio of atoms
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Answer:

Mass of Rb-87 is 86.913 amu.

Explanation:

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