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iogann1982 [59]
1 year ago
6

A current of 5. 68 a is passed through a Fe(NO3)2 solution. How long, in hours, would this current have to be applied to plate o

ut 7. 20 g of iron?
Chemistry
1 answer:
daser333 [38]1 year ago
8 0

There are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

Calculation ,

Given ; Current ( I ) = 5. 68 A

In Fe(NO_{3} )_{2} , the valancy of Fe is +2 .

2 moles of e^{-} are required for the decomposition of 1 mole of Fe .

7. 20 g  of Fe in moles  = 7. 20 g /55.845 g/mol =0.12 mole

x moles of  e^{-} are required for the decomposition of 0.128 mole of Fe .

moles of   e^{-} are required = 0.256 moles

Charge on 1 mole  of   e^{-} = 96500 C

Charge on 0.256  mole  of   e^{-} = 24704 C

Current ( I )= Q/t  

t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr

Therefore , there are  1.2 hr would this current have to be applied to plate out 7. 20 g of iron .

To learn more about iron

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How many moles of oxygen are formed when 58.6 g of KNO3 decomposes according to the following reaction? 4 KNO3(s) → 2 K2O(s) + 2
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0.725 mol

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Therefore,

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The free energy change for the following reaction at 25 °C, when [Cr3+] = 1.32×10-3 M and [Fe3+] = 1.14 M, is 131 kJ: Cr3+(1.32×
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E°cell = - 1.3575 V

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Explanation:

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<u>For a given chemical reaction if-</u>

1. ΔG = negative and E°cell = positive

⇒ <em>The reaction is spontaneous and proceeds spontaneously in the forward direction.</em>

2.  ΔG = positive and E°cell = negative

⇒ <em>The reaction is non-spontaneous and proceeds spontaneously in the reverse direction.</em>

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Cr³⁺(1.32 × 10⁻³ M) + Fe²⁺(aq) → Cr²⁺(aq) + Fe³⁺(1.14 M)

ΔG = + 131 × 10³ J ⇒ positive

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<u>Therefore, this reaction is spontaneous in the reverse direction.</u>

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