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2 years ago

The $15 million land deal that took place as a result of the Treaty of Guadalupe Hidalgo was known as

Chemistry

1 answer:

adoni [48]2 years ago

6 0

Answer:

Revolution of Guadlupe

Explanation:

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What is the density of a sample of a substance with a volume of 120ml<br> and a mass of 90g?

tigry1 [53]

Answer:

<h3>The answer is 0.75 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 90 g

volume = 120 mL

We have

$density = \frac{90}{120} = \frac{9}{12} = \frac{3}{4} \\$

We have the final answer as

Hope this helps you

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2 years ago

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Vaselesa [24]

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2 years ago

TIMED TEST PLEASE HURRY!!! The development of a new experimental method is most likely to change a theory if it makes it possibl

uysha [10]

Answer:

1. analyze the samples while they are frozen

stuff can react differently when it's colder

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2 years ago

Read 2 more answers

2Ag + H2S ? Ag2S + H2 Which statement is true about this chemical equation? A) Ag (silver) is oxidized and H (hydrogen) is reduc

nadezda [96]

Answer:

It is A).

Explanation:

Silver (Ag) goes from the pure metal to Ag+ losing 1 electron so it is oxidised.

The hydrogen ion gains electrons and is reduced.

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2 years ago

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Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500=193000C$ is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

$14\times 1000g=14000g$ of copper is deposited by = $\frac{193000}{63.5}\times 14000=42551181 C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

$40.0=\frac{42551181 C}{t}\\\\t=1063779sec$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $1063779s\times \frac{1hr}{3600s}=295hr$

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0

3 years ago