How do you find three consecutive even integers with a sum of -84. Please help!
2 answers:
3 consecutive even integers : x, x + 2, x + 4 x + (x + 2) + (x + 4) = -84.....combine like terms 3x + 6 = - 84.......subtract 6 from each side 3x = -84 - 6 3x = - 90...divide both sides by 3 x = -90/3 x = -30 x + 2 = -30 + 2 = -28 x + 4 = -30 + 4 = -26 so ur 3 numbers are : -26, -28, -30
Since they are consecutive even integers, they would differ by 2. Let the first even integer be x. x , x + 2, x + 4 Sum = -84 x + x + 2 + x + 4 = -84 x + x + x + 2 + 4 = -84 3x + 6 = -84 3x = -84 - 6 3x = -90 x = -90/3 x = -30 Hence the even integers are: x, x + 2 , x + 4 -30, -30 + 2, -30 + 2 + 2 -30, -28, -26 Hence the consecutive even integers are: -30, -28, -26
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