How do you find three consecutive even integers with a sum of -84. Please help!
2 answers:
3 consecutive even integers : x, x + 2, x + 4 x + (x + 2) + (x + 4) = -84.....combine like terms 3x + 6 = - 84.......subtract 6 from each side 3x = -84 - 6 3x = - 90...divide both sides by 3 x = -90/3 x = -30 x + 2 = -30 + 2 = -28 x + 4 = -30 + 4 = -26 so ur 3 numbers are : -26, -28, -30
Since they are consecutive even integers, they would differ by 2. Let the first even integer be x. x , x + 2, x + 4 Sum = -84 x + x + 2 + x + 4 = -84 x + x + x + 2 + 4 = -84 3x + 6 = -84 3x = -84 - 6 3x = -90 x = -90/3 x = -30 Hence the even integers are: x, x + 2 , x + 4 -30, -30 + 2, -30 + 2 + 2 -30, -28, -26 Hence the consecutive even integers are: -30, -28, -26
You might be interested in
Answer:
that's a hundred and three because n which is the variable * 100 + 3 equals 103
4, 10, 4, 10. 10*4 gives area of 40. 10+10+4+4 gives 48 as shown in question
Answer:
the number of weeks is unknown the A represents the number of weeks so the answer is 100a
Answer:
3, 10
Step-by-step explanation:
1.
5x-1=14 ->
5x=15 ->
x=3.
2.
15+3x=45 ->
3x=45-15=30 ->
3x=30 ->
x=10.
Hope that help! :)
Answer:
1.5
Step-by-step explanation: