Question

Polygon ABCDE is an irregular pentagon. Find the perimeter of the polygon. Round to the nearest tenth. Round to give final answer only.

Answer 1

Answer:

13.9 units

Step-by-step explanation:

AB = sqrt(2² + 3²) = sqrt(13)

BC = sqrt(2² + 2² = sqrt(8)

CD = sqrt(1² + 2²) = sqrt(5)

DE = 3

EA = sqrt(1² + 2²) = sqrt(5)

Add all these:

13.9 units

Answer 2

Answer:

12.9

Step-by-step explanation:

AB = $\sqrt{2^{2}+3^{2} }$ = $\sqrt{13}$

BC = $\sqrt{2^{2}+2^{2} }$ = $2\sqrt{2}$

CD = $\sqrt{1^{2}+2^{2} }$ = $\sqrt{5}$

DE = 3

EA = $\sqrt{1^{2} + 2^{2} }$ = $\sqrt{5}$

The sum of all of these (in decimal form) is (approx.) 12.9