Two opposing reactions occur at the same rate
Answer:
The Greeks invented the two main components of watermills, the waterwheel and toothed gearing, and used, along with the Romans, undershot, overshot and breastshot waterwheel mills.
Explanation:
please mark me brainliest
The percentage yield of the reaction : 93.3%
Mass of FeCO₃ 2310.44 g
<h3>Further explanation
</h3>
The reaction equation is the chemical formula of reagents and product substances
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products
Reaction
4 FeCO₃ + O₂ ⇒ 2 Fe₂O₃ + 4CO₂
MW FeCO₃ : 115,854 g/mol
MW Fe₂O₃ : 159,69 g/mol
![\tt \dfrac{35}{115.854}=0.302](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B35%7D%7B115.854%7D%3D0.302)
![\tt \dfrac{2}{4}\times 0.302=0.151](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B2%7D%7B4%7D%5Ctimes%200.302%3D0.151)
![\tt 0.151\times 159.69=24.113~g](https://tex.z-dn.net/?f=%5Ctt%200.151%5Ctimes%20159.69%3D24.113~g)
![\tt \dfrac{22.5}{24.113}\times 100\%=93.3\%](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B22.5%7D%7B24.113%7D%5Ctimes%20100%5C%25%3D93.3%5C%25)
mol of 1 kg Fe₂O₃ = 1000 g
![\tt \dfrac{1000}{159.69}=6.262](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B1000%7D%7B159.69%7D%3D6.262)
mol of FeCO₃
![\tt \dfrac{4}{2}\times 6.262=12.524](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B4%7D%7B2%7D%5Ctimes%206.262%3D12.524)
mass of FeCO₃
![\tt 12.524\times 115.854=1450.955~g](https://tex.z-dn.net/?f=%5Ctt%2012.524%5Ctimes%20115.854%3D1450.955~g)
a purity of 62.8%
![\tt \dfrac{100}{62.8} \times 1450.955=2310.44~g](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B100%7D%7B62.8%7D%20%5Ctimes%201450.955%3D2310.44~g)
Both feed into other bodies of water
Answer:
of the stock solution would be required.
Explanation:
Assume that a solution of volume
contains a solute with a concentration of
. The quantity
of that solute in this solution would be:
.
For the solution that needs to be prepared,
. The volume of this solution is
. Calculate the quantity of the solute (magnesium chloride) in the required solution:
.
Rearrange the equation
to find an expression of volume
, given the concentration
and quantity
of the solute:
.
Concentration of the solute in the stock solution:
.
Quantity of the solute required:
.
Calculate the volume of the stock solution that would contain the required
of the magnesium chloride solute:
.