3 years ago

Which of the following demonstrates that reactants and products are chemically different? Choose all that apply

Chemistry

2 answers:

nataly862011 [7]3 years ago

6 0

Your answers would be k^+1, Cl2 and F-1

Hope this helps. Kinda winged it with my research.

Lorico [155]3 years ago

5 0

It is only two answers so it is K+1 and F-1

You might be interested in

During and exothermic reaction, energy is _______ the surroundings.

Kitty [74]

Your answer is A mixed with.

4 0

3 years ago

Which is a balanced chemical equation? A. C7H16 + 5O2 6CO2 + 4H2O B. C7H16 + 11O2 7CO2 + 8H2O C. C7H16 + 14O2 7CO2 +5H2O D. C7H1

nadya68 [22]

Answer:

$\boxed{\text{B.}}$

Explanation:

$\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O$

BALANCED. 7C, 16H, and 22O on each side of equation.

$\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O$

NOT BALANCED. 7C on left and 6C on right.

$\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O$

NOT BALANCED. 16H on left and 10H on right.

$\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O$

NOT BALANCED. 7C on left and 14C on right.

3 0

3 years ago

What is the potential energy of a 2 kg plant that is on a windowsill 1.3 m high

gulaghasi [49]

Answer:

P.E = 25.48 J

Explanation:

Given data:

Mass = 2 Kg

Height = 1.3 m

Potential energy = ?

Solution:

Formula:

P.E = m . g . h

P. E = potential energy

m = mass in kilogram

g = acceleration due to gravity

h = height

Now we will put the values in formula.

P.E = m . g . h

P.E = 2 Kg . 9.8 m /s² . 1.3 m

P.E = 25.48 Kg. m² / s²

Kg. m² / s² = J

P.E = 25.48 J

8 0

3 years ago

Read 2 more answers

Why did the United States government set aside land for the first national parks?

Elan Coil [88]

B) They worries people would destroy the animals and land.

3 0

3 years ago

First person with the right answer gets brainliest thanks (btw the numbers on the right are the answers choose the right one)

kap26 [50]

Molar mass of FE2O3=2(55.85)+3(16)=159.7

2.56g*1mol/159.7*2mol/1mol*55.85g/1mol=1.79g

6 0

3 years ago