Answer:

Explanation:
Hello!
In this case, since the reaction between sulfur and oxygen is:

Whereas there is a 1/2:8 mole ratio between oxygen and SO3, and we can compute the produced grams of product as shown below:

Best regards!
75.0 degrees Celsius = 75.0 + 273 = 348 K.
Assuming pressure is held constant,

3 mole of O2 produce=2 iron oxide
0.5 of O2 produce=x
0.5 X 2/3
X=0.33 mole of iron oxide
Answer:
this is literally highschool questions. why u lying XD
Explanation:
Answer:
![[HCl]_{eq}=0.05M](https://tex.z-dn.net/?f=%5BHCl%5D_%7Beq%7D%3D0.05M)
Explanation:
Hello,
In this case, for the given chemical reaction, the law of mass action at equilibrium results:
![Kc=\frac{[H_2]_{eq}[Cl_2]_{eq}}{[HCl]^2_{eq}}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2%5D_%7Beq%7D%5BCl_2%5D_%7Beq%7D%7D%7B%5BHCl%5D%5E2_%7Beq%7D%7D)
Next, in terms of the change
due to reaction extent, it is rewritten, considering an initial concentration of HCl of 0.25M (1mol/4L), as:

Thus, solving for
via quadratic equation or solver, the following results are obtained:

Clearly, the solution is
as the other result will provide a negative concentration for the hydrochloric acid at equilibrium, thereby, its equilibrium concentration turns out:
![[HCl]_{eq}=0.25M-2*0.1M](https://tex.z-dn.net/?f=%5BHCl%5D_%7Beq%7D%3D0.25M-2%2A0.1M)
![[HCl]_{eq}=0.05M](https://tex.z-dn.net/?f=%5BHCl%5D_%7Beq%7D%3D0.05M)
Best regards.