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andre [41]
3 years ago
14

I GIVE MORE POINTS WHO ANSWER THIS QUESTION. Which option describes a wavelength of light? (1 point) O a distance between two si

milar points on a wave of light O a type of visible light O an object that makes light bend or bounce O a heated atom that forms light​
Chemistry
1 answer:
Mkey [24]3 years ago
8 0

Answer:

It's the first option. A distance between two similar points on a wave of light.

Explanation:

On a wavelength chart, where you measure the rate at which the light travels at its distance from the source. You have two points to compare to.

You might be interested in
How many grams of sulfur trioxide are produced 18 mol O2 react with sufficient sulfur? Show all your work S8 +12O 2> 8SO3
SOVA2 [1]

Answer:

m_{SO_3}=2.31x10^4gSO_3

Explanation:

Hello!

In this case, since the reaction between sulfur and oxygen is:

S_8 +\frac{1}{2} O_2 \rightarrow 8SO_3

Whereas there is a 1/2:8 mole ratio between oxygen and SO3, and we can compute the produced grams of product as shown below:

m_{SO_3}=18molO_2*\frac{8molSO_3}{1/2molO_2} *\frac{80.06gSO_3}{1molSO_3} \\\\m_{SO_3}=23,057.3gSO_3=2.31x10^4gSO_3

Best regards!

7 0
3 years ago
If the volume of a gas is 958 mL at 75.0 C, at what temperature would the volume of the gas decrease to 822 mL
zhenek [66]

75.0 degrees Celsius = 75.0 + 273 = 348 K.

Assuming pressure is held constant,

\frac{958}{348}=\frac{822}{T_{2}}  \\ \\ \frac{348}{958}=\frac{T_{2}}{822} \\ \\ T_{2}=\frac{(822)(348)}{958} \approx 299 \text{ K} \\ \\ T_{2} \approx 299-273=\boxed{26^{\circ} \text{ C}}

3 0
2 years ago
4Fe+3O2-->2Fe2O3. How many moles of fe2o3 are produced from 0.5 moles of o2?
Yuliya22 [10]
3 mole of O2 produce=2 iron oxide
0.5 of O2 produce=x
0.5 X 2/3
X=0.33 mole of iron oxide
5 0
3 years ago
What is this help ASAP
Natalka [10]

Answer:

this is literally highschool questions. why u lying XD

Explanation:

8 0
3 years ago
A reaction begins with 1.00 mol of HCl in a 4.00 liter container at a certain temperature.
lubasha [3.4K]

Answer:

[HCl]_{eq}=0.05M

Explanation:

Hello,

In this case, for the given chemical reaction, the law of mass action at equilibrium results:

Kc=\frac{[H_2]_{eq}[Cl_2]_{eq}}{[HCl]^2_{eq}}

Next, in terms of the change x due to reaction extent, it is rewritten, considering an initial concentration of HCl of 0.25M (1mol/4L), as:

4.00=\frac{(x)(x)}{(0.25-2x)^2}

Thus, solving for x via quadratic equation or solver, the following results are obtained:

x_1=0.1M\\x_2=0.17M

Clearly, the solution is x=0.1M as the other result will provide a negative concentration for the hydrochloric acid at equilibrium, thereby, its equilibrium concentration turns out:

[HCl]_{eq}=0.25M-2*0.1M

[HCl]_{eq}=0.05M

Best regards.

3 0
3 years ago
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