Answer is: 31,45%.
mrs₁(C₉H₁₆O₄-<span>azelaic acid) = 12g.
mr</span>₂(C₉H₁₆O₄) = 50g.
ω₂(C₉H₁₆O₄) = 15% = 0,15.
mrs₂(C₉H₁₆O₄) = mr₂·ω₂ = 50g·0,15 = 7,5g.
mrs₃(C₉H₁₆O₄) = mrs₁ + mr₂ = 12g + 7,5g = 19,5g.
mr₃ = mr₂ + mr₂ = 50g + 12g = 62g.
ω₃ = mrs₃÷mr₃ = 19,5g ÷ 62g = 31,45% = 0,3145.
Answer:
Explanation:
An atom is the smallest indivisible particle that takes part in any chemical reaction. They are easily identified distinctively as elements in a compound.
The subscripts accompanying a chemical symbol shows the number of atoms of elements combining to give a compound:
Compound Elements Number of atoms
KBr K Br 2
C₁₂H₂₂O₁₁ 12(C) 22(H) 11(O) 12 + 22 + 11 = 45
KAlSi₃O₈ 1(K) 1(Al) 3(Si) 8(O) 1 + 1 + 3 + 8 = 13
Ag₃PO₄ 3(Ag) 1(P) 4(O) 3+ 1 + 4 = 8
CH₃CO₂C₆H₄COOH 9(C) 8(H) 4(C) 9+8+4 = 21
The Coefficients are the numbers that are before a variable/constant
The reactants are l2 and O2
The products are l4O9.
Answer:
93.33 g of Fe
Explanation:
The balanced equation for the reaction is given below:
4Fe + 3O₂ —> 2Fe₂O₃
Next, we shall determine the masses of Fe and O₂ that reacted from the balanced equation. This can be obtained as follow:
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 4 × 56 = 224 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ from the balanced equation = 3 × 32 = 96 g
SUMMARY:
From the balanced equation above,
224 g of Fe reacted with 96 g of O₂.
Finally, we shall determine the mass of Fe required to react with 40 g of O₂. This can be obtained as follow:
From the balanced equation above,
224 g of Fe reacted with 96 g of O₂.
Therefore, Xg of Fe will react with 40 g of O₂ i.e
Xg of Fe = (224 × 40)/96
Xg of Fe = 93.33 g
Therefore, 93.33 g of Fe is required to react with 40 g of O₂.
<h3>
Answer:</h3>
4649.16 g
<h3>
Explanation:</h3>
We are given;
- The equation for the reaction
2C₄H₁₀ + 13O₂→ 8CO₂ + 10H₂O
We are required to determine the mass of water produced.
<h3>
Step: Determine the number of moles of C₄H₁₀</h3>
We know that, moles = Mass ÷ Molar mass
Molar mass of C₄H₁₀ is 58.14 g/mol
Therefore;
Moles of C₄H₁₀ = 3000 g ÷ 58.14 g/mol
= 51.5996
= 51.60 moles
<h3>Step 2: Determine the number of moles of water </h3>
- From the equation, 2 moles of C₄H₁₀ reacts to produce 10 moles of water
Therefore;
Moles of water = Moles of C₄H₁₀ × 10/2
= 51.60 moles × 5
= 258 moles
<h3>Step 3: Determine the mass of water produced </h3>
We know that; mass = moles × molar mass
Molar mass of water = 18.02 g/mol
Thus;
Mass of water = 258 moles × 18.02 g/mol
= 4649.16 g
Therefore, the mass of water produced will be 4649.16 g