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n200080 [17]
3 years ago
10

PLZ HURRY IT'S URGENT!!!!!!!

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

B. 12 and 25 is the answer.....

Hope this helps!

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Answer: 62
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Ecuaciones con resultado 17
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Step-by-step explanation:

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2 years ago
Using Euler's relation, derive the following relationships:a. Cosθ=½(e^jθ+e^−jθ)b. Sinθ=½(e^jθ−e(^−jθ)
Montano1993 [528]

Answer:

a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]

Step-by-step explanation:

a.We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Adding both equations, we have

e^jθ = cosθ + jsinθ

+

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ

Simplifying, we have

e^jθ + e^(-jθ) = 2cosθ

dividing through by 2 we have

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b. We know that

e^jθ = cosθ + jsinθ and

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Subtracting both equations, we have

e^jθ = cosθ + jsinθ

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e^(-jθ) = cosθ - jsinθ

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Simplifying, we have

e^jθ - e^(-jθ) = 2jsinθ

dividing through by 2 we have

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4 0
3 years ago
-\frac{9x}{4}=27
IRISSAK [1]

\bf \cfrac{-9x}{4}=27\implies \stackrel{\textit{cross multiplying}}{-9x=4(27)}\implies x=\cfrac{4(27)}{-9}\implies x=4\cdot \cfrac{27}{-9} \\\\\\ x=4\cdot -3\implies x=-12

4 0
2 years ago
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