Answer
Let f(x) = ax + b
Then
f(x + 1) = a(x + 1) + b
= ax + a + b
Hence, a = 3, and a + b = 5, b = 2
f(-2) = 3(-2) + 2
= -6 + 2
= - 4
f(2x) = 3(2x ) + 2
= 6x + 2
Answer:
4600
Step-by-step explanation:
This is an arithmetic sequence with common difference d between consecutive terms.
d = - 2 - (- 6) = 2 - (- 2) = 6 - 2 = 4
The sum to n terms of an arithmetic sequence is
= 
[ 2a + (n - 1)d ]
where a is the first term
here a = - 6, d= 4 and n = 50, hence
= 
[ (2 × - 6) + (49 × 4) ]
= 25 ( - 12 + 196 )
= 25 × 184
= 4600
5x = x^2 + 4
x^2 - 5x + 4 = 0
(x - 4)(x - 1) = 0
x = 4, 1
(x + 6)^2 = 100
x + 6 = +/1 sqrt100
x + 6 = +/- 10
x = 4, -16
<span><span>Step 1: Find a number you can multiply by the bottom of the fraction to make it 10, or 100, or 1000, or any 1 followed by 0s.
</span><span>Step 2: Multiply both top and bottom by that number.
</span><span>Step 3.Then write down just the top number, putting the decimal point in the correct spot (one space from the right hand side for every zero in the bottom number)</span></span><span>
Hope i helped :[)</span>
