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Scilla [17]
3 years ago
11

The larger of two consecutive integers is 7 greater than twice the smaller. Find the integers.

Mathematics
1 answer:
belka [17]3 years ago
4 0

Answer:

8,9

Step-by-step explanation:

(x +1) + 7=2x

x+8 = 2x

8=x

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How many solutions is there for 8 + 9p = 9p - 7
spin [16.1K]

Answer: There are no solutions.

Step-by-step explanation: So the way you do this is by subtracting 9p from both sides, which gets you:

8 = -7

Since 8 is not equal to -7, there is no solution to this equation.

4 0
3 years ago
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A recent article in the paper claims that business ethics are at an all-time low. Reporting on a recent sample, the paper claims
dedylja [7]

Answer:

The correct solution is "0.127128".

Step-by-step explanation:

The given values are:

p = 0.31

n = 20

Now,

p(8

                     =20C_{9}(0.31)^9\times (0.69)^{11}+20C_{10}(0.31)^{10}\times (0.69)^{10}+20C_{11}\times (0.31)^{11}\times (0.69)^{9}

=0.074955+0.037043+0.015130

=0.127128

5 0
2 years ago
25.6% of what # is 21.12
laila [671]
To solve this problem, we are going to use the percent proportion, a/b = p/100, where a is the part of a number b, the whole, and p is the percentage out of 100.  
When we fill in our known integers into this equation, we get

21.12 / b = 25.6 / 100

Next, to simplify this equation, we should use cross products (means - extremes products theorem).  This means multiplying the numerator of one fraction and the denominator of the other fraction and setting them equal to one another.

21.12(100)=25.6(b)

When we multiply, you get

2112 = 25.6b

Finally, we divide both sides by 25.6, to get our variable b, alone, and without a coefficient.

82.5 = b

Therefore, 25.6% of the number 82.5 is 21.12.
7 0
3 years ago
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Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3
polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256

#learnwithBrainly

8 0
3 years ago
a. Are the following triangles congruent? If so, which postulate or theorem proves this? b. What transformation moved one triang
xenn [34]

Answer:

Yes by SAS

Step-by-step explanation:

If you look at the triangles they have 2 side lenght in common (and since it is a right triange they have all the sides in commmon) and they share an angel

In other words 2 sides are conurent with an angle betwene them.

You would need to rotait the shape 90 degrese.

4 0
2 years ago
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