The manager of a baseball team has 15 players to choose from for his 9 person batting order
2 answers:
Given the question:
The manager of a baseball team has 15 players to choose from for his 9-person batting order. How many different ways can he arrange the players in the lineup?
5,005 362,880 3,603,600 1,816,214,400
The number of was in which a smaller group is choosing from a bigger group is given by the bigger number combination the smaller number.
Here, we want to choose a 9-person batting order from a team of 15 players. This is given by:
The manager of a baseball team has 15 players to choose from for his 9-person batting order. How many different ways can he arrange the players in the lineup?
5,005 362,880 3,603,600 1,816,214,400
The number of was in which a smaller group is choosing from a bigger group is given by the bigger number combination the smaller number.
Here, we want to choose a 9-person batting order from a team of 15 players. This is given by:
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Answer:
$525
Step-by-step explanation:
We can find the original price by using the formula x - 0.36x = 336, where x is the original price, 0.36 is the discount percentage (converted to decimal form), and 336 is the total amount paid after the discount is applied:
To check and further understand why the formula works, we can simply apply the discount to the original price and subtract the number from the original price:
525 * 0.36 = 189
525 - 189 = 336
Modeling the first formula gives us:
525 - (0.36 * 525) = 336
525 - 189 = 336