<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer:
y = - 3x + 19
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 3, thus
y = - 3x + c ← is the partial equation
To find c substitute (6, 1) into the partial equation
1 = - 18 + c ⇒ c = 1 + 18 = 19
y = - 3x + 19 ← equation of line
Answer:
3*x-9
Difference means subtraction and times means multiplication!
Simplify it to 2x-4=8x-4
-6x=0
x=0
not sure if that counts as no solution or single solution though...
