A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s. A
t the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s. Projectile motion formula: h = -16t2 + vt + h0 t = time, in seconds, since the ball was thrown h = height, in feet, above the ground { complete the system that models the heights of the ball and the receiver's hands over time.
A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s
⇒ and v= 14 ft/s
Substitute these given values we have;
It is also given that at the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s.
⇒ and v= 10 ft/s
then;
Therefore, the system that models the heights of the ball and the receiver's hands over time :
x = 55, because if you look the whole entire bar is 180° in total but you dont have to worry about that because that's not what the question is wanting you to look at, If you look really close there is a half and half on both sides so that means there is a 90° angle so you would have to take 90-35 and that is what gives you your missing angle which is 55.
