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Ilia_Sergeevich [38]
3 years ago
5

Alicia sells bracelets b for $5 each, and necklaces n for $10 each. In one day she sells 15

Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer:

5b+n=100,6+10n=15 that's all

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There are four more women than men at a golf club.
marissa [1.9K]

Answer: I think its 4 + 2m

5 0
3 years ago
Abel saved 43 more nickels than dimes. After he spent 17 dimes he had twice as many nickels than dimes. How many coins did he ha
Alborosie

Answer:

180 coins

Explanation:

N = number of nickels (no nickels spent)

D = number of dimes initially saved

D' = number of dimes left after spending

1) N = D + 43

2) D' = D - 17

3) N = 2*D' = 2*(D - 17)

Set equations 1) and 3) equal to each other and solve for D:

D + 43 = 2*(D - 17)

D + 43 = 2*D - 34

D = 43 + 34 = 77

N = D + 43 = 77 + 43 = 120 nickels left

D' = D - 17 = 77 - 17 = 60 dimes left

Total coins left = 120 + 60 = 180 coins (I hope this is not too confusing for you)

8 0
2 years ago
Suppose z is proportional to the square root of x. If z = 717 when x = 9, find the proportionality constant k.??
Dahasolnce [82]

Answer:

  239

Step-by-step explanation:

Write the equation. Fill in the given values, and solve for the unknown,

  z = k√x

  717 = k√9

  k = 717/3 = 239

The constant of proportionality is 239.

8 0
2 years ago
Read 2 more answers
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
Someone help with this one please.
kodGreya [7K]

The think the answer for number 7 is A/10

Number 8 is C/16

5 0
3 years ago
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