Question

What is the solution of the equation 4(3-x)^4/3-5=59

Answer 1

The solution is x=−5

Answer 2

Answer:

Given the equation:   $4(3-x)^{\frac{4}{3}} -5 = 59$

Add 5 to both sides we have;

$4(3-x)^{\frac{4}{3}} = 64$

Divide by 4 both sides we have;

$(3-x)^{\frac{4}{3}} =16$

or

$3-x = (16)^{\frac{3}{4}$

Using exponent rules;

$a^{\frac{n}{m}} = (\sqrt[m]{a})^n$

then;

$3-x =( \sqrt[4]{16})^3$

Simplify:

$3-x = (2)^3$

or

$3-x = 8$

subtract 3 from both sides we have;

$-x = 5$

Divide both sides by -1 we get

$x = -5$

Therefore, the solution for the given equation is, -5