Six cakes cost £1.80.How Much do ten cakes cost

Mathematics

2 answers:

Tanzania [10]2 years ago

8 0

Answer: Cost of 10 cakes is £3.

Step-by-step explanation:

Since we have given that

Cost of 6 cakes = £ 1.80

Using unitary method,

Cost of 1 cake is given by

£1.80 ÷ 6= £0.30

So, Cost of 10 cakes would be

£0.30 × 10 = £3

Hence, Cost of 10 cakes is £3.

german2 years ago

5 0

First find the value of 1 cake by dividing the price of all six by six. £1.80/6 can be seen more simply as 180p/6 which is 30p. Therefore 1 cake is 30p. Multiply this by ten and you have 300p, or £3.00. Ten cakes cost £3 :)

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Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and t

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Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.

How long will it take for this population to grow to a hundred rodents? To a thousand rodents?

Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

$\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}$

Seperate the differential equation and solve for the constant C.

$\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2} }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}$