The previous answer from another person got deleted, so I'm here to put it back in my own words.
(Edit: The answer is A)
First of all, you can take 4 out of each, so simplify everything by 4.
4(x^4 - 6x^3 + 9x^2)
Next, you can see that you're able to take out x^2
4x^2(x^2 - 6x + 9)
You can see that both x^2 and 9 are perfect squares, meaning you can crunch them together like this
(x+3)^2 or (x-3)^2
Of course, only one would work, and as fate has it, (x-3)^ produces x^2 - 6x + 9
This would turn the now factored equation into :
4x^2(x-3)^2 or 4x^2(x-3)(x-3), this means the answer is A
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
The ordered pairs that make this equation true is (4, 10)
A linear equation is given by:
y = mx + b;
where y, x are variables, m is the slope of the line and b is the y intercept.
Given the linear equation: y = 10x - 30:
At (1, -12): y = 10(1) - 30 = -20 ≠ -12
At (8, 1): y = 10(8) - 30 = 50 ≠ 1
At (4, 10): y = 10(4) - 30 = 10
At (6, 20): y = 10(6) - 30 = 30 ≠ 20
The ordered pairs that make this equation true is (4, 10)
Find out more at: brainly.com/question/13911928
Answer: A: there is not enough evidence to support a relationship between lunch preference and role at school