Answer:
( 0.6 t^2 + 3t + 11 ) cm
Step-by-step explanation:
dh/dt = 1.2t + 3
at t = 0, h = 11 cm
(a)
dh / dt = 1.2 t + 3
dh = (1.2 t + 3) dt
integrate on both sides
h = 0.6 t^2 + 3t + c .... (1)
where c is the integrating constant
put t = 0
11 = c
Put in equation (1) , we get
h = ( 0.6 t^2 + 3t + 11 ) cm
Thus, teh height of tree after t years is given by
( 0.6 t^2 + 3t + 11 ) cm.
Hello :
1/(√6 -1) = (√6 +1)/(√6 -1)(√6 +1) = (√6 +1)/(√6)²-1² ) = (√6 +1)/5
Answer:
4 1/24
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given
See attachment for complete question
Required
Determine the difference between the shortest and the longest
This question implies that we calculate the range.

From the table, we have:


So, we have:

