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Yuki888 [10]
3 years ago
12

Pleas help me!!

Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0
1) Answer: The part of the quadratic formula tells us whether the quadratic equation can be solved by factoring is b^2-4ac

2) 4x^2+6x+2=0
ax^2+bx+c=0; a=4, b=6, c=2
b^2-4ac=(6)^2-4(4)(2)=36-32
b^2-4ac=4

Answer: b^2-4ac=4
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32) Out of 525 people surveyed, 210 answered yes. Estimate how many people would answer yes if 900
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A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
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Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

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mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

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