Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Step-by-step explanation:
Sp = rs 800
loss = 10%
Cp = ?
we know that,
cp= sp×100÷ 100-L%
= 800×100÷100-10
= 80000÷90
= 888.89#
Notice that we can calculate the area of the square and the rectangle separately to get the following:
therefore, the total area is 27 in^2
Answer:
M = 8.85
Step-by-step explanation:
10 - 1.15 = 8.85
Answer: N=0
Step-by-step explanation:
0=−5n−2n
Rewrite the equation as −5n−2n=0. -5n−2n=0 S<em>ubtract 2n from −5n</em>. −7n=0 Divide each term by −7 and simplify.
