In order to find the vertical asymptotes of a rational function you must set the denominator = 0 and solve for x.
If F(x) = (3x + 9) / (x^2 + 4x - 12), then set x^2 + 4x - 12 = 0 and solve for x.
(x + 6)(x - 2) = 0
x + 6 = 0 so then x = -6
x - 2 = 0 so then x = 2
For this particular function, you have 2 vertical asymptotes. x = -6 and x = 2
He will have $13.5
Explanation:
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Answer 83
Step-by-step explanation:
9514 1404 393
Answer:
C. 3x∛(y²z)
Step-by-step explanation:
The relevant rules of exponents are ...
![\sqrt[n]{a^m} = a^\frac{m}{n}\\\\(a^b)^c=a^{bc}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20a%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%28a%5Eb%29%5Ec%3Da%5E%7Bbc%7D)
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Your expression can be rewritten and simplified as follows.
![\displaystyle\sqrt[3]{27x^3y^2z}=(3^3x^3y^2z)^\frac{1}{3}=3xy^\frac{2}{3}z^\frac{1}{3}=3x(y^2z)^\frac{1}{3}=\boxed{3x\sqrt[3]{y^2z}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B27x%5E3y%5E2z%7D%3D%283%5E3x%5E3y%5E2z%29%5E%5Cfrac%7B1%7D%7B3%7D%3D3xy%5E%5Cfrac%7B2%7D%7B3%7Dz%5E%5Cfrac%7B1%7D%7B3%7D%3D3x%28y%5E2z%29%5E%5Cfrac%7B1%7D%7B3%7D%3D%5Cboxed%7B3x%5Csqrt%5B3%5D%7By%5E2z%7D%7D)
Answer:
if you have the value of x then y =x +7