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k0ka [10]
4 years ago
11

1)

Mathematics
1 answer:
MrRissso [65]4 years ago
7 0

Answer:

Step-by-step explanation:

The diagram of the triangles are shown in the attached photo.

1) Looking at ∆AOL, to determine AL, we would apply the sine rule

a/SinA = b/SinB = c/SinC

21/Sin25 = AL/Sin 105

21Sin105 = ALSin25

21 × 0.9659 = 0.4226AL

AL = 20.2839/0.4226

AL = 50

Looking at ∆KAL,

AL/Sin55 = KL/Sin100

50/0.8192 = KL/0.9848

50 × 0.9848 = KL × 0.8192

KL = 49.24/0.8192

KL = 60

AK/Sin25 = AL/Sin 55

AKSin55 = ALSin25

AK × 0.8192 = 0.4226 × 50

AK = 21.13/0.8192

AK = 25.8

2) looking at ∆AOC,

Sin 18 = AD/AC = 18/AC

AC = 18/Sin18 = 18/0.3090

AC = 58.25

Sin 85 = AD/AB = 18/AB

AB = 18/Sin85 = 18/0.9962

AB = 18.1

To determine BC, we would apply Sine rule.

BC/Sin77 = 58.25/Sin85

BCSin85 = 58.25Sin77

BC = 58.25Sin77/Sin85

BC = 58.25 × 0.9744/0.9962

BC = 56.98

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Find the value of the expression 0.5^10/0.5^7
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Answer:

The solution is:

  • \frac{0.5^{10}}{0.5^7}=0.125

Step-by-step explanation:

Given the expression

0.5^{10}\div 0.5^7

Solving

\frac{0.5^{10}}{0.5^7}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

so

\frac{0.5^{10}}{0.5^7}=0.5^{10-7}

\mathrm{Subtract\:the\:numbers:}\:10-7=3

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\frac{0.5^{10}}{0.5^7}=0.125

7 0
3 years ago
If $450 is invested at 6% compounded A (annually), B (quarterly), C (monthly), what is the amount after 7 years? How much intere
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Answer:

Step-by-step explanation:

Here's the gameplan for this.  First of all we need a general formula, then we will define the variables for each.

The general formula for all of these is the same:

A(t)=P(1+\frac{r}{n})^{nt}

where A(t) is the amount after the compounding, P is the initial investment, n is the number of compoundings per year, r is the interest rate in decimal form, and t is time in years.  

Then after we find the amount after the compounding, we will subtract the initial amount from that, because the amount at the end of the compounding is greater than the initial amount.  It's greater because it represents the initial amount PLUS the interest earned.  The difference between the initial amount and the amount at the end is the interest earned.

For A:

A(t) = ?

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n = 1

r = .06

t = 7

A(t)=450(1+\frac{.06}{1})^{(1)(7)}

Simplifying gives us

A(t)=450(1.06)^7

Raise 1.06 to the 7th power and then multiply in the 450 to get that

A(t) = 676.63 and

I = 676.63 - 450

I = 226.63

For B:

A(t) = ?

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n = 4 (there are 4 quarters in a year)

r = .06

t = 7

A(t)=450(1+\frac{.06}{4})^{(4)(7)}

Simplifying inside the parenthesis and multiplying the exponents together gives us

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A(t) = ?

P = 450

n = 12 (there are 12 months in a year)

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A(t)=450(1+\frac{.06}{12})^{(12)(7)}

Simplifying the parenthesis and the exponents:

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Adding inside the parenthesis and raising to the 84th power and multiplying in 450 gives you that

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Step-by-step explanation:

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