Answer:
what i have lerned in this module
Answer:
C 10⁴
Step-by-step explanation:
The given equation is
![7.75n = 77500](https://tex.z-dn.net/?f=7.75n%20%3D%2077500)
Javier has to solve for n
He can multiply through by 100 to get;
![775n = 7750000](https://tex.z-dn.net/?f=775n%20%3D%207750000)
He can now divide through by 775 to obtain:
![n = \frac{7750000}{775}](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B7750000%7D%7B775%7D%20)
He can now easily simplify to get:
![n = 10000](https://tex.z-dn.net/?f=n%20%3D%2010000)
We rewrite as a power to get:
![n = {10}^{4}](https://tex.z-dn.net/?f=n%20%3D%20%20%7B10%7D%5E%7B4%7D%20)
Well for 3. you use the Pythagorean theorem to say that 28^2 - 18^2= x^2 so 21.4 and for 4. the Pythagorean theorem says a^2 + b^2 = c^2 with c being the hypotenuse of any right triangle so the sums of the two smaller squares make the sum of the larger square making the answer b
Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.
![H_0: s^2 = 300\\H_a: s^2 \neq 300](https://tex.z-dn.net/?f=H_0%3A%20s%5E2%20%3D%20300%5C%5CH_a%3A%20s%5E2%20%5Cneq%20300)
(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic = ![\frac{(n-1)s^2}{\sigma^2} \\=62.4](https://tex.z-dn.net/?f=%5Cfrac%7B%28n-1%29s%5E2%7D%7B%5Csigma%5E2%7D%20%5C%5C%3D62.4)
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.
Answer:
0 (zero)
Step-by-step explanation:
Plug in the variable for -4 and solve
y= 2(-4)2-4(-4)
y= -8(2)-4(-4)
y=-16+16
y=0