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maks197457 [2]
3 years ago
10

Plot the line for the equation on the graph. y−2=−2(x+4)

Physics
1 answer:
svetoff [14.1K]3 years ago
5 0

Like and comment down if that was helpful

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Answer:

1,860

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3 years ago
If a 42kg rolling object slows from 11.5 m/s to 3.33 m/s how much work does friction do?
lara31 [8.8K]

Explanation:

work done by friction = 1/2 x 42 x ( 3.33^2 - 11.5^2)

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= 21 ( - 121.17 )

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4 0
3 years ago
What is the difference in KE between a 52.5 kg person running 3.50 m/s and a 0.0200 kg bullet flying 450 m/s?
rusak2 [61]

Answer:

Ek = 1705.28 [J]

Explanation:

In order to solve this problem, we must remember that kinetic energy can be calculated by means of the following equation.

E_{k}=\frac{1}{2} *m*v^{2}

where:

m = mass [kg]

v = velocity [m/s]

Ek = kinetic energy [J] (Units of Joules)

<u>For the person running</u>

<u />E_{k} =\frac{1}{2}*52.2*(3.5)^{2} \\ E_{k} =319.72[J]<u />

<u />

<u>For the bullet</u>

<u />E_{k} =\frac{1}{2} *m*v^{2}<u />

<u />E_{k} =\frac{1}{2} *0.02*(450)^{2} \\E_{k}=2025 [J]<u />

<u />

The difference in Kinetic energy is equal to:

Ek = 2025 - 319.72

Ek = 1705.28 [J]

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3 years ago
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