A grocery store owner is planning a display by stacking cans of soup in a pyramid. The top row of the stack will have 1 can, the
1 answer:
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Answer:
The value of x = 0.41
Step-by-step explanation:
∵
Let
∴
∴ 6y² - 5y = 6
∴ 6y² - 5y - 6 = 0 ⇒ factorize
∴ (3y + 2)(2y - 3) = 0
∴ 3y + 2 = 0 ⇒ 3y = -2 ⇒ y = -2/3
∴ 2y - 3 = 0 ⇒ 2y = 3 ⇒ y = 3/2
∵
∴ ⇒ refused
( never gives -ve values)
∵ ⇒ insert <em>ln</em> in both sides
∵ ⇒ <em>ln</em>(e) <em>= 1</em>
∴
∴ x = ln(3/2) = 0.41
(a) Probability of getting a queen from a deck of 52 cards =
(b) Probability of getting a red card from a deck of 52 cards =
(c) Probability of getting a queen or a red card from a deck of 52 cards =
<u>Solution:</u>
Given that card is drawn from a standard deck of 52 cards.
Need to determine probability of getting
(a) queen (b) red (c) a queen or a red card
<em><u>(a) Calculating probability of getting a queen from a deck of 52 cards </u></em>
Favorable events are getting a queen of spade, heart , diamond or club.
Means number of favorable events = 4
Total events is all possible outcomes from 52 cards
So Total number of event = 52
<em><u>(b) Calculating probability of getting a red card from a deck of 52 cards </u></em>
Number of red cards are 13 cards of diamonds and 13 cards of heart = 13+13 =26
So number of favorable event = 26
Total number of event = 52
<em><u>(c) Calculating probability of getting a queen or red card from a deck of 52 cards </u></em>
Favorable events are 26 red cards + two queens of spade and club. Need to keep in mind that queens of heart and diamond is already considered in 26 red cards.
So number of favorable event = (26+2) = 28
Total number of event = 52
<em><u>Summarizing the result :</u></em>
(a) Probability of getting a queen from a deck of 52 cards =
(b) Probability of getting a red card from a deck of 52 cards =
(c) Probability of getting a queen or a red card from a deck of 52 cards =