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MaRussiya [10]
3 years ago
14

Identfy the equation that translates Y= In(x) five units down.

Mathematics
1 answer:
mariarad [96]3 years ago
3 0

Answer:

y= In(x)-5

Step-by-step explanation:

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Determine which of the ordered pair is a solution for the equation 2x-3y=7
Vikentia [17]
<h3><u>The correct answer is: B.</u></h3>

We could use a graphing calculator to solve this easily, but let's just solve it by looking at the equation.

We'll need to turn this standard form equation into a slope-intercept form equation to be able to easily solve it.

Isolate y.

2x - 3y = 7

<em><u>Add 3y to both sides.</u></em>

2x = 3y + 7

<em><u>Subtract 7 from both sides.</u></em>

3y = 2x - 7

<em><u>Divide both sides by 3.</u></em>

y = 2/3x -7/3

Now, we can plug each x value in the answer choices into x to find the corresponding y value.

y = 2/3(7) - 7/3 = 2.34

As this y value does not match, A is not the answer.

y = 2/3(-4) - 7/3 = -5

This y value does match, so B is the correct answer.

y = 2/3(-9) - 7/3 = -8.34

This y value doesn't match either, so C is not the answer.

y = 2/3(9) - 7/3 = 3.67

This y value doesn't match either, so D is not the answer.

7 0
3 years ago
Whats a comparison between the value of the 3 in 17,235 and the value of 3 in 17,352?
rjkz [21]

Answer: The 3 in 17,235 is in the tens digit and the 3 in 17,352 is in the hundreds digit

8 0
3 years ago
Factor Completely.<br> 30r^2 + 30r + 75.
kari74 [83]

Answer:

15(2r^2+2r+5)

Step-by-step explanation:

I'm more of a guess and check type of person, but 15 x 2r^2 = 30r^2, 15 x 2r = 30r, and 15 x 5 = 75

6 0
3 years ago
A hyperbola has its center at (0,0), a vertex of (20,0 and an asymptote of y= 13/20x. find the equation that describes the hyber
photoshop1234 [79]

Answer:

\frac{x^2}{20^2} -\frac{y^2}{13^2} =1

Step-by-step explanation:

Given that a hyperbola has its centre at (0,0)

Asymptote = y =13x/20

Vertex is on x axis thus a =20

Hence hyperbola will have equation as

\frac{x^2}{20^2} -\frac{y^2}{b^2} =1

Asymptotes would be

\frac{x^2}{20^2} -\frac{y^2}{b^2} =0

Or y=bx/20

Comparing with given equation we get b =13

Hence asymptote would have equation as

\frac{x^2}{20^2} -\frac{y^2}{13^2} =1\\\frac{x^2}{400} -\frac{y^2}{169} =1

4 0
3 years ago
I need answers to all please!! I really appreciate it.
EleoNora [17]

Answer:

19. 4(x-4)

20. 6(3k+7)

21. prime

22. 4(5m-2n)

23. 14p-14= 14(p-1)

24. 35+5r= 5(7+r)

25. 10x - 14y= 2(5x- 7y)

3 0
3 years ago
Read 2 more answers
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