Hello!
To find the x-intercepts of the function, y = x² - 15, we need to make the y-value of the function equal to zero, and then we can solve for the x-intercepts.
0 = x² - 15
There are many ways to approach this question. You could factor, take the square root, use the quadratic formula, or graph the equation.
In standard form, a normal quadratic equation would be like this: y = Ax² + Bx + C. But, in this equation, there is no "Bx" term. So, the easiest way to solve for the x-intercepts is to take the square root of both sides.
1. Isolate the variable to one side of the equation.
0 = x² - 15 (add 15 to both sides)
15 = x²
2. Take the square root of both sides.
√15 = √x²
x = ±√15
√15 is about 3.87298..., which is rounded to 3.9.
-√15 is about -3.97298..., which is rounded to -3.9.
Therefore, the x-intercepts of the function, y = x² -15, are (3.9, 0) and (-3.9, 0).
