Please, I need help with this!!!
2 answers:
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Answer:
The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.
Thus, domain of f(x): x∈R = range of f¯¹(x)
and range of f(x): x∈R =domain of f¯¹(x)
Answer:
{2, 8}
Step-by-step explanation:
We want to find x for ...
15 = 4|x -5| +3
12 = 4|x -5| . . . . subtract 3
3 = |x -5| . . . . . . divide by 4
±3 = x -5 . . . . . . show the meaning of absolute value
5 ±3 = x = {2, 8} . . . . . add 5
The values of x for which f(x) = 15 are 2 and 8.
