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3 years ago

Where on a number line are the numbers x for which |x|>1

Mathematics

1 answer:

Andrews [41]3 years ago

6 0

Answer:

Step-by-step explanation:

Given the inequality

|x|> 1

The modulus of x shows that x can be both positive and negative value.

If x is positive:

x>1

1<x

If x is negative:

-x>1

Multiplying both sides of the inequality by minus will change the inequality sign

x < -1

Combining both inequalities:

1<x<-1

Find the position on the number line in the attachment

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Please help I have no idea what I'm doing with any of this!!

jasenka [17]

Answer: you are doing hell jesus

Step-by-step explanation:

6 0

2 years ago

544ml^2 is how many liters<br><br>show your work

ivolga24 [154]

Answer:

295.936

Step-by-step explanation:

First find out what 544^2 is. That is 295,936. There are 100 ml in 1 liter. So divide 295,936 by 100 to see how many liters are in 295,936 ml.

295,936÷100=295.936

7 0

2 years ago

A woman is randomly selected from the 18–24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally

Naddik [55]

Answer:

$X \sim N(114.8,13.1)$

Where $\mu=114.8$ and $\sigma=13.1$

We are interested on this probability

$P(X>140)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

$P(z>1.924)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(114.8,13.1)$

Where $\mu=114.8$ and $\sigma=13.1$

We are interested on this probability

$P(X>140)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this: $P(X>140)=P(\frac{X-\mu}{\sigma}>\frac{140-\mu}{\sigma})=P(Z>\frac{140- 1114.8}{2.6})=P(z>1.924)$ And we can find this probability using the complement rule: