Where on a number line are the numbers x for which |x|>1
1 answer:
Answer:
Step-by-step explanation:
Given the inequality
|x|> 1
The modulus of x shows that x can be both positive and negative value.
If x is positive:
x>1
1<x
If x is negative:
-x>1
Multiplying both sides of the inequality by minus will change the inequality sign
x < -1
Combining both inequalities:
1<x<-1
Find the position on the number line in the attachment
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Answer:
Option D
Step-by-step explanation:
Given that a producer ships boxes of produce to individual customers.(say x)
X is a normal random variable with mean = 36 and std dev =4 lbs
By definition of std normal variate we know that
is N(0,1)
75th percentile of std normal distribution is
0.675
Hence corresponding x would be
Option D matches with this value
Hence answer is option D
Answer:
(-√(6-√26) < x < √(6-√26)) ∪ (x < -√(6 +√26)) ∪ (√(6 +√26) < x)
Step-by-step explanation:
Using x^2 = z, the equation can be rewritten as ...
z^2 -12z +10 > 0
(z -6)^2 -26 > 0
|z -6| > √26
This resolves to two equations.
This one ...
x^2 -6 < -√26 . . . . substitute x^2 for z
|x| < √(6-√26) . . . . add 6, take the square root; use √a^2 = |a|
-√(6-√26) < x < √(6-√26)
__
and this one ...
x^2 -6 > √26
|x| > √(6 +√26)
x < -√(6 +√26) ∪ √(6 +√26) < x
