Add 2z to both sides. you get
6k-2z+2z=12+2z
6k=2z+12
divide both sides by 6
6k/6=2z+12 divide by 6
your answer is k=1/3z+2
i hope it helps!
Answer:
19.4
Step-by-step explanation:
I haven't done this type of equation in awhile but I believe you can multiply 8 and 17 then divide it by 7 to find the missing number. It might be correct but I am not 100% sure.
Answer:
Step-by-step explanation:
Well the probability would be 1/6 because you have 6 numbers on a 6 sided regular dice. And you only have one 5, so it would be a 1/6 chance since you have one 5 but 6 different numbers you could choose from.
Answer : 1/6
Axis of symmetry: x=1
Vertex: (1, -24)
Explanation:
6x²-12x-25=-7
6x²-12x-18=0
a=6, b=-12, c=-18
Formula of axis of symmetry: x=-b/2a
x=-b/2a
x= -(-12)/2(6)
x= 12/12
x= 1
Vertex: (1,?)
Sub x= 1 into the equation,
6(1)² - 12(1) - 18 = y
6 - 12 - 18 = y
y = -24
Answer:
a. 7 Ω
b. 5 Ω
c. 4.472 Ω
Step-by-step explanation:
a. Since we have two resistors in with resistances R = 4Ω and R' = 3 Ω in series, the total impedance z of the circuit is the sum of the individual resistances.
So, z = R + R' = 4 Ω + 3Ω = 7 Ω
b. Since we have a resistor of resistance R = 4Ω in series with an inductor of reactance X = 3 Ω, the total impedance is z = √(R² + X²)
z = √((4 Ω)² + (3 Ω)²)
z = √(16 Ω² + 9 Ω²)
z = √(25 Ω²)
z = 5 Ω
c. Since we have a resistor of resistance R = 4Ω in series with an inductor of reactance X = 3 Ω, and a capacitor of reactance, X' = 1 Ω the total impedance is z = √[R² + (X - X')²]
z = √((4 Ω)² + (3 Ω - 1 Ω)²)
z = √(16 Ω² + (2 Ω)²)
z = √(16 Ω² + 4 Ω²)
z = √(20 Ω²)
z = √(4 × 5) Ω
z = √4 × √5 Ω
z = 2√5 Ω
z = 4.472 Ω