Answer: 65
Step-by-step explanation:
All those angles added up have to equal 360 degrees.
The little square on the angle to the left of x means that it's a right angle, or 90 degrees.
360
- 180
= 180 <--- this is the bottom half,
180
- 90 <--- the right angle on the left
= 90
90
-25
= 65 <--- that's x
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
How to determine average velocity and instantaneous velocity?
Average velocity is defined as the body's overall displacement divided by its time of motion. While instantaneous velocity is defined as a body's speed at a certain instant in time, or its displacement at that instant. When the velocity is constant, average and instantaneous velocities will equalize at just one condition.
The definition of instantaneous velocity is the rate of change of position over a relatively brief time period (almost zero). Simply said, the speed of an object at that precise moment. The definition of instantaneous velocity is "The velocity of an item in motion at a certain point in time." The instantaneous velocity of an object may be equal to its standard velocity if it has uniform velocity.
Mathematically, average velocity = [s(t₂) - s(t₁)]/[t₂ - t₁]
Instantaneous velocity at time, t is = (ds/dt) at time = t
Given, the displacement for the particle is given by s = 3t² - 4t + 5
Time interval, t₁ = 5s and t₂ = 3s;
Using formula in literature, average velocity of the particle in the time interval between 3s and 5s is:
Average velocity = (s(5) - s(3))/(5 - 3) = (60 - 20)/2 = 20 ms⁻¹
Instantaneous velocity at t = 4 is ds/dt at that time-frame:
Now, v = ds/dt = 6t -4
Now, v(4) = 6(4) - 4 = 20 ms⁻¹
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
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Answer:
The standard deviation for the number of students who work full time = 8.38
Step-by-step explanation:
Given data
Sample size n = 284
No. of students work full time is P = 55 % = 0.55
No. of students who not work full time is Q = 100- 55 % = 45 % = 0.45
The standard deviation is given by
Put all the values in above equation we get
S.D. = 8.38
This is the standard deviation for the number of students who work full time.
If this helps...
1/4 of the pie is eaten... and 3/4 of the pie is not eaten or still left.