Answer : He spends 2 hours doing paperwork each day.
Hope this helps. - M
Answer:
Step-by-step explanation:
1) The other curve is 
then the common points of both curves are x-intercepts, the roots of 
2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:
Answer:
Step-by-step explanation:
You need to find the set of points that will yield a slope that is the negative reciprocal of the slope of Line L because perpendicular lines have negative reciprocal slopes. The negative reciprocal of 13/7 is -7/13. Which set of points will produce this result? The formula for finding the slope is:
m = (y2 - y1)/(x2 - x1)
Consider the second set of coordinates.
(2 - (-5))/(-7 - 6) = (2 + 5)/(-13) = -7/13
The second set of coordinates satisfy the condition.
9:
r
15.5 (not the one with the line under it i just couldnt find the one that didnt have the line under it)
for the graph, put 16 on the right side and label the lines right to left 16 15.5 14 14.5 etc. Put an open circle on the 15.5 line. then make an arrow pointing to the left.
10:
80p+64
This is because she needs 80 points OR MORE and (p represents the points) she already has 64. She needs 80 to be less than or equal to the amount of points earned.
The solution is 16p because 80-64=16 and p is needs to be greater than or equal to 16
Scores are {72, 97, 82, x} where x is the unknown fourth score
They add up to 72+97+82+x = x+251
Divide this sum over four because there are four scores we want to average out. We end up with (x+251)/4 = M where M is the mean. Asa wants the mean to be 82, so make M = 82.
We can replace M with 82 and solve for x like so
(x+251)/4 = M
(x+251)/4 = 82
x+251 = 4*82
x+251 = 328
x = 328-251
x = 77
Asa needs a score of 77 on the fourth test so that the mean of the four tests is 82. If she scores higher than 77 on the fourth test, then the mean will be larger than 82.
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Depending on what your teacher is looking for, the first step is to establish your variable. So you would say "let x = fourth score". However, that seems too easy. So perhaps your teacher is looking for the equation (x+251)/4 = 82 or some variant of it.
