So, first determine what half of the denominator or bottom number would be.
Half of 13 would be 6.5 (Do 13 divided by 2).
Next, see if the numerator or top number on the fraction is smaller, the same, or bigger than that number.
Since 6.5 is bigger than 6, the numerator would be smaller.
If it is smaller, keep the whole number (in this case 12) the same. If it is the same or equal, round up (in this case 13).
Since 6 is smaller than 6.5, you keep 12 the same.
Your answer would be 12.
Hope this helped!
To solve for the confidence interval for the true average
percentage elongation, we use the z statistic. The formula for confidence
interval is given as:
Confidence interval = x ± z σ / sqrt (n)
where,
x = the sample mean = 8.63
σ = sample standard deviation = 0.79
n = number of samples = 56
From the standard distribution tables, the value of z at
95% confidence interval is:
z = 1.96
Therefore substituting the known values into the
equation:
Confidence interval = 8.63 ± (1.96) (0.79) / sqrt (56)
Confidence interval = 8.63 ± 0.207
Confidence interval = 8.42, 8.84
<span> </span>
There are 105 in 6th grade because there are 75 boys right? So it said the ratio of girls is 7 and the ratio of boys is 5 so I divided 75 to 5 = 15 and I multiply 7 to 15 and got 105 girls.
Answer: $129
Step-by-step explanation: First, you round 2.75 up to 3 and then you multiply by 43. Boom, $129.
(2x²<span> + 3x - 4) + (8 - 3x) + (-5x</span>²<span> + 2)
= </span> 2x² + 3x - 4 + 8 - 3x - 5x² + 2
= -3x² + 6
= 3(-x² + 2)
