Solve the equation tanxtan(x – 45°)=0 for 0° < x < 360°.

Mathematics

1 answer:

Lady_Fox [76]3 years ago

4 0

Answer:

\tan \left(\frac{\sin \left(x\right)-\cos \left(x\right)}{\cos \left(x\right)+\sin \left(x\right)}\right)

Step-by-step explanation:

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Daniel [21]

Step-by-step explanation:

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2 years ago

20. what us the area of the figure:

Varvara68 [4.7K]

If the angle in B is 45º, that means the angle in A is also going to be 45º, considering it's a right triangle, so AC and BC are they have the same length.
Then using Pythagoras, you'll get that $AC^{2} + BC^{2}$ equals $AB^{2}$ .
Now, you know that AC=BC and that AB=24.
So you'll get $2AC^{2} =24^2$ . You do the square root in both sides and you get that 2AC=24 and AC=12.

Now that you know that both AC and BC equal 12, you can find the area by just multiplying them and then diving them by 2. (The formula for the area of a triangle is half base multiplied by height, and in a right triangle, if a cathetus is the base, the other cathetus will be the height)

And so the area is equal to 72.

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3 years ago

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prisoha [69]

<h3>Given:</h3>