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Marysya12 [62]
3 years ago
7

HELP MEEEE !!! Plsssss

Mathematics
1 answer:
liberstina [14]3 years ago
6 0
Answer: option B

This is because you have to work out the range of both periods

The range is the highest number - the lowest number

Range for period 1: 92-81=11
Range for period 3:92-74=18

As you can see the range for period 3 is 7 points greater than period 1 therefore the answer is the second option ( option B)

Hope this helped
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It costs $3.75 for 25 oz. of candy or $6.30 for 90 oz. of candy. Which is
Art [367]

Answer:

90 OZ.

Step-by-step explanation:

You have to divide the ounces by the price to see how much $1 per ounce costs.

25 divided by 3.75 = 6.6 Ounces for $1

90 divided by 6.30 = 14.28 ounces for $1

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3 years ago
Write an equation or inequality to represent "five times the difference of a number n and forty two is ten more than twice the p
IRINA_888 [86]

Five times the difference of a number n and forty two is ten more than twice the product of a number x and number y

  • Five times: 5 ×
  • difference of a number n and forty two: (n - 42)
  • is: =
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  • ten more than: + 10

Rewrite the expression into an equation.

<h3>5(n - 42) = 2(xy) + 10</h3>
3 0
3 years ago
Read 2 more answers
Can someone pls help
Tom [10]
5 balls = 3.1 pounds
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6 0
3 years ago
A triangle ABC has A(1,-4) B(3,-1) C(3,-8).Find the length of the sides AB and AC
mr_godi [17]

Answer:

Step-by-step explanation:

AB=\sqrt{(1^{2} -3^{2})+((-4)^{2} -(-1)^{2} ) }

     =\sqrt{7}

AC=\sqrt{(3^{2} -1^{2} )+((-8)^{2}- (-4)^{2} )} \\

     =\sqrt{56}

4 0
3 years ago
Aziza has a triangle with two sides measuring 11 in. and 15 in. She claims that the third side can be any length as long as it i
irina [24]

Answer:

Aziza’s claim is incomplete. The third side must be between 4 in. and 26 in.

Step-by-step explanation:

With the Triangle Inequality Theorem, saying that the sum of lengths of any two sides of a triangle is greater than the length of the third side. With this we can develop two inequalities:

11 + 15 > x

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rewrite this as x < 26

11 + x > 15

x > 15 - 11   Subtract 11 from both sides

x > 4

Therefore, the third side can be anywhere greater than 4 inches and less than and less than 26 inches.

4 <  x < 26

4 0
3 years ago
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