Distrivute 0.2 to x and +50 and you get 0.2x+10-6 now for the other side we do the same and we get 1.2x+8 or an easier way... Let's solve your equation step-by-step.<span><span><span>0.2<span>(<span>x+50</span>)</span></span>−6</span>=<span>0.4<span>(<span><span>3x</span>+20</span>)</span></span></span>Step 1: Simplify both sides of the equation.<span><span><span>0.2x</span>+4</span>=<span><span>1.2x</span>+8</span></span>Step 2: Subtract 1.2x from both sides.<span><span><span><span>0.2x</span>+4</span>−<span>1.2x</span></span>=<span><span><span>1.2x</span>+8</span>−<span>1.2x</span></span></span><span><span><span>−x</span>+4</span>=8</span>Step 3: Subtract 4 from both sides.<span><span><span><span>−x</span>+4</span>−4</span>=<span>8−4 </span></span><span><span>−x</span>=<span>4 now you divide by negative x (technically it is -1x=4 so your answer is x=-4</span></span>
Answer:
1.1 gigabytes
Step-by-step explanation:
Let us represent:
The number of gigabytes = g
Under his cell phone plan, Owen pays a flat cost of $67.50 per month and $4 per gigabyte. He wants to keep his bill at $71.90 per month.
The Equation is given as:
$71.90 = $67.50 + $4 × g
71.90 = 67.50 + 4g
71.90 - 67.50 = 4g
4.4 = 4g
x = 4.4/4
x = 1.1 gigabytes
Therefore, the number of gigabytes of data Owen can use while staying within his budget is 1.1 gigabytes
Answer:
y = -1/10x^2 +2.5
Step-by-step explanation:
The distance from focus to directrix is twice the distance from focus to vertex. The focus-directrix distance is the difference in y-values:
-1 -4 = -5
So, the distance from focus to vertex is p = -5/2 = -2.5. This places the focus 2.5 units below the vertex. Then the vertex is at (h, k) = (0, -1) +(0, 2.5) = (0, 1.5).
The scale factor of the parabola is 1/(4p) = 1/(4(-2.5)) = -1/10. Then the equation of the parabola is ...
y = (1/(4p))(x -h) +k
y = -1/10x^2 +2.5
_____
You can check the graph by making sure the focus and directrix are the same distance from the parabola everywhere. Of course, if the vertex is halfway between focus and directrix, the distances are the same there. Another point that is usually easy to check is the point on the parabola that is even with the focus. It should be as far from the focus as it is from the directrix. In this parabola, the focus is 5 units from the directrix, and we see the points on the parabola at y=-1 are 5 units from the focus.
The similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line include:
- Both methods involve making a 90-degree angle between two lines.
- The methods determine a point equidistant from two equidistant points on the line.
<h3>What are perpendicular lines?</h3>
Perpendicular lines are defined as two lines that meet or intersect each other at right angles.
In this case, both methods involve making a 90-degree angle between two lines and the methods determine a point equidistant from two equidistant points on the line.
Learn more about perpendicular lines on:
brainly.com/question/7098341
#SPJ1
