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noname [10]
3 years ago
9

I’m literally struggling like can someone hel me plz this is due tomorrow

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Check the picture below.

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One rule of thumb for estimating crowds is that each person occupies 2.3 square feet. Use this value to estimate the size of a c
dybincka [34]

Answer:

150,595

Step-by-step explanation:

First, convert miles to feet:

4.1 mi × (5280 ft/mi) = 21648 ft

The area that the crowd takes up is:

2 × 8 ft × 21648 ft = 346368 ft²

The number of people is:

346368 ft² × (1 person / 2.3 ft²) = 150594.8

Rounding to the nearest integer, there are approximately 150,595 people in the crowd.

7 0
3 years ago
(SAT prep) Find the value of x in each case of the following exercises:
yKpoI14uk [10]

The value of x from the figure is 70°

<h3>How to determine the value</h3>

It is important to note that alternate angles are equal and angles in a triangle sum up to 180°

We then have that,

x + 50 + 60 = 180 °

x + 110 = 180°

Make 'x' subject

x = 180 - 110

x = 70 °

Thus, the value of x from the figure is 70°

Learn more about alternate angles here:

brainly.com/question/24839702

#SPJ1

8 0
2 years ago
The Hawks are starting a babysitting business. They charge an initial deposit of $25 and a rate of $4 an hour. A linear model is
Sauron [17]
What’s the question so I can answer it.
7 0
3 years ago
I. A rhombus is a special type of square. II. A rectangle is a special type of rhombus. III. A trapezoid is a special type of pa
Kobotan [32]

Answer: I. only

--------------------------------------------------------------------------------------------------------------

Explanation :

II. False. a rectangle is a special type of rhombus since a rhombus has all sides equal, while a rectangle has all angles equal. A rhombus has opposite angles equal, while a rectangle has opposite sides equal.  The diagonals of a rhombus intersect at equal angles, while the diagonals of a rectangle are equal in length.

I.  True. A square is a special case of a rhombus, because it has four equal-length sides and goes above and beyond that to also have four right angles. Every square you see will be a rhombus, but not every rhombus you meet will be a square.

III. False.  Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. A trapezoid can never be a parallelogram. The correct answer is that all trapezoids are quadrilaterals.

4 0
3 years ago
Solve this equation. 5n+7=7(n+1)-2n
9966 [12]
Distribute 7 to both n and 1

7(n + 1) = 7n + 7

5n + 7 = 7n + 7 - 2n

Combine like terms

5n + 7 = 7n - 2n + 7

5n + 7 = 5n + 7

If you want to solve for n, subtract 7 from both sides

5n + 7 (-7) = 5n + 7 (-7)

5n = 5n

then divide 5 from both sides

5n/5 = 5n/5

n = n

Effectively, this equation is <em>unsolvable</em>

hope this helps
3 0
3 years ago
Read 2 more answers
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