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makkiz [27]
3 years ago
6

Note: Your teacher will grade your response to ensure that you receive proper credit for your answer. The cost of a telephone ca

ll is $0.75 + $0.25 times the number of minutes. Write an algebraic expression that models the cost of a telephone call that lasts t minutes.
Mathematics
2 answers:
Contact [7]3 years ago
6 0
0.75+0.25t

because 0.75 is the flat rate of the amount of money it takes to make a call... and 0.25t is how much money it will take based on how long the call us.

t= the number of minutes
Mnenie [13.5K]3 years ago
5 0

Answer:

0.75+0.25t

Step-by-step explanation:

simple algebra

You might be interested in
By how much in total value is the 1 in 87 614 greater than 4?
77julia77 [94]

Answer:

10

Step-by-step explanation:

14=10 + 4

14-4 =10

....................

8 0
3 years ago
Write a function rule in terms of x and y for the line that contains the points (-7.4, -9.7) and ( 8.4, 6.1) .
Karo-lina-s [1.5K]

Answer:

y = x + -2.3

x = -y - 2.3 (but why would one need this?...)

Step-by-step explanation:

(6.1 - (-9.7))/(8.4 - (-7.4)) = 15.8/15.8 = 1

6.1 = 8.4 + b

b = -2.3

8 0
3 years ago
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
3 years ago
Determine whether the measures 2, √8, and √12 can be the measures of the sides of a triangle. If so, classify the triangle as ac
gtnhenbr [62]

Answer:

C

Step-by-step explanation:

First check if the triangle is right.

If the square of the longest side is equal to the sum of the squares on the other 2 sides then the triangle is right.

longest side = \sqrt{12} and (\sqrt{12} )² = 12

2² + (\sqrt{8} )² = 4 + 8 = 12

Thus the triangle is right → C

7 0
3 years ago
Read 2 more answers
The correct expression for a number which is 9 times as big as the number obtained after p has been increased
defon

Answer:

9(p + 4)

Step-by-step explanation:

One of the unknown variable is p.

First of all, we know that the number is 9 times as big (multiplication) as the new number obtained through the addition of four to p i.e (p + 4).

Translating the word problem into an algebraic expression, we have;

9 * (p + 4) = 9(p + 4)

Simplifying further, we have;

9p + 36

4 0
3 years ago
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