The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
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Answer:
m∠QRS = 52°
Step-by-step explanation:
From the given figure,
In right triangles ΔRQT and ΔRST,
QT = TS = 7.5 units [Given]
RT ≅ RT [Reflexive property]
ΔRQT ≅ ΔRST [By HL theorem of congruence]
Therefore, m(∠QRT) = m(∠SRT) = 26° [CPCTC]
m(∠QRS) = 2m(∠QRT)
= 2×(26°)
= 52°
Answer:
-212.5
Step-by-step explanation:
-212.5 x 0.4 = -85
Given that <span>Henry divided the town into eight regions and randomly chose 10 households from each region in order to survey about traffic concerns. This type of sample is called</span> stratified sampling.
Stratified sampling<span> is a type of </span>sampling <span>method where</span><span> the researcher divides the population into separate groups, called strata and then, a probability </span>sample<span> (often a simple random </span>sample<span> ) is drawn from each group.</span>