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OLEGan [10]
3 years ago
7

Gloria works at least 10 hours per week but no more than 25 hours each week. She earns 9.00 an hour. Her weekly earnings depend

on how many hours she works. What is the range of this function
Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0

Answer:

[90,225] notation or 135 range

Step-by-step explanation:

10x9=90

25x9=225

[900,2250] notation or 1350 range

You might be interested in
A statistician chooses 27 randomly selected dates, and when examining the occupancy records of a particular motel for those date
Anni [7]

Answer:

Confidence interval variance [21.297 ; 64.493]

Confidence interval standard deviation;

4.615, 8.031

Step-by-step explanation:

Given :

Variance, s² = 34.34

Standard deviation, s = 5.86

Sample size, n = 27

Degree of freedom, df = 27 - 1 = 26

Using the relation for the confidence interval :

[s²(n - 1) / X²α/2, n-1] ; [s²(n - 1) / X²1-α/2, n-1]

From the chi distribition table :

X²α/2, n-1 = 41.923 ; X²1-α/2, n-1 = 13.844

Hence,

[34.34*26 / 41.923] ; [34.34*26 / 13.844]

[21.297 ; 64.493]

The 95% confidence interval for the population variance is :

21.297 < σ² < 64.493

Standard deviation is the square root of variance, hence,

The 95% confidence interval for the population standard deviation is :

4.615 < σ < 8.031

3 0
3 years ago
Write an equation of the line passing through the points ( -5, -25 ),(0,0), and( 3,15)?
Akimi4 [234]

Answer:

Y=5X because the slope is 5 and the Y-intercept is 0

6 0
2 years ago
Please hurry!! If you do answer, thank you.
stiv31 [10]

????????????????????

8 0
3 years ago
Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)​<br><br>PLEASE HELP!
EleoNora [17]

Answer:

\bold {$\dfrac{7}{44}$}

Step-by-step explanation:

<h3> Reciprocal:</h3>

    \sf \text{The reciprocal of any number $\dfrac{a}{b}$ is given by $\dfrac{b}{a}$}\\\\5\dfrac{1}{2}=\dfrac{11}{2}\\\\\text{Reciprocal of $\dfrac{11}{2}$  = $\dfrac{2}{11}$}

<h3>Additive inverse:</h3>

 \text{Additive inverse of $\dfrac{-7}{8}$=$\dfrac{7}{8}$}

        Now multiply,

          \sf \dfrac{7}{8}*\dfrac{2}{11}=\dfrac{7}{4}*\dfrac{1}{11}\\

                      =\dfrac{7}{44}

7 0
2 years ago
I need the answer please. Because I think i got mine wrong
Gekata [30.6K]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

• a^{-m} ⇔ \frac{1}{a^{m} }

• a^{0} = 1

• a^{m} × a^{n} ⇔ a^{(m+n)}

Given

(a)

8^{-2} = \frac{1}{8^{2} }

(b)

\frac{1}{3^{-3} } = 3³

(c)

6^{-12} × 6^{8} × 6^{0}

= 6^{(-12+8)} × 1

= 6^{-4}

= \frac{1}{6^{4} }

7 0
3 years ago
Read 2 more answers
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