Answer:
See the step-by-step explanation
Step-by-step explanation:
Let c be any element of C. (I'm not sure wether you have to assume that C is non-empt or not)
C is a subset of B. That means that as c is in C, it is also in B. ()
Now, B is a subset of A. It follows that as .
That means c is an element of A. The predicate Q is true for all elements of A, including c.
Because we let c be any element of C, we have proven that the predicate Q is true for all elements in C.
Answer:
Therefore, HL theorem we will prove for Triangles Congruent.
Step-by-step explanation:
Given:
Label the Figure first, Such that
Angle ADB = 90 degrees,
angle ADC = 90 degrees, and
AB ≅ AC
To Prove:
ΔABD ≅ ΔACD by Hypotenuse Leg theorem
Proof:
In Δ ABD and Δ ACD
AB ≅ AC ……….{Hypotenuse are equal Given}
∠ADB ≅ ∠ADC ……….{Each angle measure is 90° given}
AD ≅ AD ……….{Reflexive Property or Common side}
Δ ABD ≅ Δ ACD ….{By Hypotenuse Leg test} ......Proved
Therefore, HL theorem we will prove for Triangles Congruent.
Answer:
Step-by-step explanation:
2A = bh
so, the required form is :