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Gelneren [198K]
3 years ago
7

I need some help, an equation would do, will give you the Brainliest answer. Thank you!

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0
They will need 2 moving trucks
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Suppose KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. Prove that A is equidistant from LM and KN.
Neporo4naja [7]

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This is proved by ASA congruent rule.

 Step-by-step explanation:

Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ

we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.

In ΔAPN and ΔAQL

∠PNA=∠ALQ    (∵alternate angles)  

AN=AL   (∵diagonals of parallelogram bisect each other)

∠PAN=∠LAQ      (∵vertically opposite angles)

∴ By ASA rule ΔAPN ≅ ΔAQL

Hence, by CPCT  i.e Corresponding parts of congruent triangles PA=AQ

Hence, A is equidistant from LM and KN.

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2 years ago
Write the word form and the expanded form for each <br><br> 1.7 &amp; 5.62
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