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ArbitrLikvidat [17]
3 years ago
10

please help with this ? Compare and contrast the compounds NH3 and PH3 in terms of bonding, molecular geometry (shape), and inte

rmolecular forces. Which substance would experience a stronger attraction between its molecules, and why?
Chemistry
2 answers:
nika2105 [10]3 years ago
6 0
 Both compounds are composed of covalent bonds and gaseous under room temperature and pressure. According to data, PH3 has a low boiling point than NH3, though the former being heavier than the later. This is due to intermolecular H- bonding in the later which is absent in the former. The oxidation state of phosphorous in PH3 is (- 3) as that for nitrogen in NH3. Both phosphine and ammonia react with oxygen to produce P2O5 gas and water, and N2 gas and water.
evablogger [386]3 years ago
3 0

Explanation: Both of these molecules are covalently bonded and are polar in nature. Since they are polar covalent molecules, they have dipole-dipole inter molecular forces of attraction.

In ammonia, N atom is the central atom and three H atoms are bonded to it and N atom has one lone pair of electrons due to which its molecular geometry is trigonal pyramidal.  Similarly, in phosphine, P is the central atom and three H atoms are bonded to it and it has one lone pair of electrons due to which its molecular geometry is trigonal pyramidal.

Nitrogen is more electron negative than phosphorous. Hydrogen boding is present in ammonia as hydrogen atoms are bonded to more electron negative nitrogen atom.

Due to the presence of hydrogen bonding, ammonia molecule experience stronger attraction forces as compared to phosphine.

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Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles O2 to the
jek_recluse [69]

Answer:

Option A says we have 4 moles of Fe for each 3 moles O2

This is correct For 3 moles of O2 consumed, we need 4 moles of Fe to be reacted

Explanation:

Step 1: Data given

Step 2: The balanced equation

4Fe + 3O2 → 2Fe2O3

Step 3: Calculate the mol ratio

For 3 moles O2 we'll have 4 moles Fe

Option A says we have 4 moles of Fe for each 3 moles O2

This is correct For 3 moles of O2 consumed, we need 4 moles of Fe to be reacted

Option b says we have 2 mole Fe2O3 for each 4 moles Fe

This doesnt say anything about O2. So doesn't apply for this question.

Option C says we have 4 moles of Fe for each 2 moles Fe2O3

This is the same as option B, so doesn't apply for this question.

Option D says for each 3 moles of O2 we have 2 Fe2O3

This is true, but doesn't say anything about Fe so doesn't apply here.

4 0
3 years ago
Read 2 more answers
1. How many grams would 8.1 x 1021 molecules of sucrose (C12H22011)<br> weigh?
Nimfa-mama [501]

Answer:

Mass = 4.6 g

Explanation:

Given data:

Number of molecules of sucrose = 8.1 ×10²¹ molecules

Mass of sucrose = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules

1.35 × 10⁻² mol

Mass of sucrose:

Mass = number of moles × molar mass

Molar mass = 342.3 g/mol

Mass = 1.35 × 10⁻² mol ×342.3 g/mol

Mass = 462.1  × 10⁻² g

Mass = 4.6 g

7 0
3 years ago
The energy released by nuclear fission can be used to ________ and turn a turbine to produce ________ energy.
enyata [817]
Heat water; mechanical (the movement of a turbine is based off of mechanical energy, not chemical or potential).
6 0
3 years ago
Read 2 more answers
According to the website of the National Aeronautics and Space Administration (NASA), the average temperature of the universe is
charle [14.2K]

Answer : The temperature in degree Celsius is, -270.45^oC

Explanation :

The conversion used for the temperature from Kelvin to degree Celsius is:

^oC=K-273.15

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in Kelvin is, 2.7

Now we have to determine the temperature in Kelvin.

^oC=K-273.15

^oC=2.7-273.15

^oC=-270.45

Therefore, the temperature in degree Celsius is, -270.45^oC

3 0
3 years ago
"How much NH4Cl, when present in 2.00 liters of 0.200 M ammonia, will give a solution with pH = 8.20? For NH3, Kb = 1.8 x 10-5"
Andru [333]

Answer:

245.66g of NH₄Cl is the mass we need to add to obtain the desire pH

Explanation:

The mixture of NH3/NH4Cl produce a buffer. We can find the pH of a buffer using H-H equation:

pH = pKa + log [A⁻] / [HA]

<em>Where [A⁻] is the molar concentration of the base, NH₃, and [HA] molar concentration of the acid, NH₄⁺. This molar concentration can be taken as the moles of each chemical</em>

<em />

First, we need to find pKa of NH₃ using Kb. Then, the moles of NH₃ and finally replace these values in H-H equation to solve moles of NH₄Cl we need to obtain the desire pH.

  • <em>pKa NH₃/NH₄⁺</em>

pKb = - log Kb

pKb = -log 1.8x10⁻⁵ = <em>4.74</em>

pKa = 14 - pKb

pKa = 14 - 4.74

pKa = 9.26

  • <em>Moles NH₃</em>

<em>2.00L ₓ (0.200mol NH₃ / L) = 0.400 moles NH₃</em>

  • <em>H-H equation:</em>

pH = pKa + log [NH₃] / [NH₄Cl]

8.20 = 9.26 + log [0.400 moles] / [NH₄Cl]

-1.06 =  log [0.400 moles] / [NH₄Cl]

0.0087 =  [0.400 moles] / [NH₄Cl]

[NH₄Cl] = 0.400 moles / 0.0087

[NH₄Cl] = 4.59 moles of NH₄Cl we need to add to original solution to obtain a pH of 8.20. In grams (Using molar mass NH₄Cl=53.491g/mol):

4.59 moles NH₄Cl ₓ (53.491g / mol) =

<h3>245.66g of NH₄Cl is the mass we need to add to obtain the desire pH</h3>

<em />

3 0
3 years ago
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