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ArbitrLikvidat [17]
3 years ago
10

please help with this ? Compare and contrast the compounds NH3 and PH3 in terms of bonding, molecular geometry (shape), and inte

rmolecular forces. Which substance would experience a stronger attraction between its molecules, and why?
Chemistry
2 answers:
nika2105 [10]3 years ago
6 0
 Both compounds are composed of covalent bonds and gaseous under room temperature and pressure. According to data, PH3 has a low boiling point than NH3, though the former being heavier than the later. This is due to intermolecular H- bonding in the later which is absent in the former. The oxidation state of phosphorous in PH3 is (- 3) as that for nitrogen in NH3. Both phosphine and ammonia react with oxygen to produce P2O5 gas and water, and N2 gas and water.
evablogger [386]3 years ago
3 0

Explanation: Both of these molecules are covalently bonded and are polar in nature. Since they are polar covalent molecules, they have dipole-dipole inter molecular forces of attraction.

In ammonia, N atom is the central atom and three H atoms are bonded to it and N atom has one lone pair of electrons due to which its molecular geometry is trigonal pyramidal.  Similarly, in phosphine, P is the central atom and three H atoms are bonded to it and it has one lone pair of electrons due to which its molecular geometry is trigonal pyramidal.

Nitrogen is more electron negative than phosphorous. Hydrogen boding is present in ammonia as hydrogen atoms are bonded to more electron negative nitrogen atom.

Due to the presence of hydrogen bonding, ammonia molecule experience stronger attraction forces as compared to phosphine.

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Analizando una biomolécula X, un científico comprueba que está formada por Carbono, Hidrógeno, Oxígeno y Nitrógeno, además de li
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Analyzing a biomolecule X, a scientist verifies that it is made up of Carbon, Hydrogen, Oxygen and Nitrogen, in addition to releasing water when it joins with other similar molecules to form polymers. Considering these antecedents, it can be inferred that biomolecule X corresponds to: A Steroids B fatty acid C nucleotide D amino acid E monosaccharide (for people who dont speak spanish)

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6 0
3 years ago
As a gas is compressed in a cylinder, the pressure of the gas
hichkok12 [17]

Answer:

As a gas is compressed in a cylinder its pressure

As the compression proceeds the volume of the chamber is decreasing and since mass is same, density increases. Similarly as volume decreases the number of gas molecules colliding with the walls increases as the density increases, so the pressure on the wall also increases.

6 0
3 years ago
A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t
drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t} (1)

<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>  

(a) We can calculate the energy (ΔU) using equation (1):

\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J  

(b) The work is related to pressure and volume by:

\Delta W = -p \Delta V

<em>where p: pressure and ΔV: change in volume = V final - V initial      </em>

\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J

(c) By the definition of Energy, we can calculate q:

\Delta U = \Delta W + \Delta q

<em>where Δq: is the heat transfer </em>

\Delta q = \Delta U - \Delta W = 7.2 J - (-5.1 \cdot 10^{2} J) = 5.2 \cdot 10^{2} J    

I hope it helps you!  

6 0
4 years ago
How many moles are present in 63.80L of oxygen gas, O2?
matrenka [14]

Answer:

2.85moles of oxygen gas

Explanation:

Given parameters:

Volume of oxygen gas  = 63.8L

Unknown:

Number of moles  = ?

Solution:

We assume that the gas is under standard temperature and pressure. To find the number of moles, use the expression below:

     1 mole of a gas at STP occupies a volume of 22.4L

 So;

       63.8L of oxygen gas will take up a volume of

              \frac{63.8}{22.4}   = 2.85moles of oxygen gas

4 0
3 years ago
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