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blagie [28]
2 years ago
12

Iupac name of h3C-C-Ch2-ch3​

Chemistry
1 answer:
pshichka [43]2 years ago
8 0

Answer:

The IUPAC name of given compound is 3−5−ethyl−5−−3−methylheptane. Explanation: The parental chain is of 7 carbons with single bonds hence it is heptane. Two substituents ethyl and methyl group are attached from an equal distance. Hence according to the alphabetical order preference, counting starts from carbon which is close to an ethyl group.

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7 0
3 years ago
Pure magnesium metal is often found as ribbons and can easily burn in the presence of oxygen. when 2.59 g of magnesium ribbon bu
stepan [7]
Burning Mg in the air and reacting with O2 forming a white powder of MnO

So the equation is going to be:
Mn + O2 ⇒ MnO (this equation is not conserved)

to make it equilibrium:
1- First we should put 2Mno to equal the O2 on both sides.
So it will be:
Mg + O2⇒ 2MgO
2- Second we should put 2Mn to equal the Mn on both sides.
2Mg + O2⇒ 2MgO (this equation is conserved)
After putting the physical states the final equilibrium equation is going to be:
                        Δ
2Mg(s) + O2(g)⇒ 2MgO(s)

 

4 0
3 years ago
1.As per the Aufbau principle, which of the following orbitals have the lowest energy?
madam [21]

The correct answer attached in file, Thank you for joining brainly community.

3 0
2 years ago
When the population of organisms in an ecosystem is in balance, we consider the ecosystem to be: A. The ecosystem is in successi
krek1111 [17]
The answer is B. Equilibrium means a state in which opposing forces or influences are balanced.
7 0
3 years ago
A group 2 metal carbonate has a mass of 84 g/mol. Identify the group 2 metal X using its chemical formula.
zepelin [54]

Answer:

Magnesium

0.003mole

Explanation:

The problem here entails we find the metal in the carbonate.

 For group 2 member, let the metal  = X;

 The carbonate is XCO₃;

 If we sum the atomic mass of the elements in the metal carbonate, we should arrive at 84g/mol

 Atomic mass of C = 12g/mol

                            O  = 16g/mol

 Atomic mass of X + 12 + 3(16)  = 84

  Atomic mass of X  = 84 - 60  = 24g/mol

The element with atomic mass of 24g is Magnesium

B.

Number of moles in 0.3g of CaCO₃:

     Molar mass of CaCO₃   = 40 + 12 + 3(16)  = 100g/mol

 Number of moles = \frac{mass}{molar mass}  

 Number of moles  = \frac{0.3}{100}   = 0.003mole

7 0
3 years ago
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