At 445 °C, Kc = 50.2. If one starts with 0.100 M H2 (g), 0.100 M I2 (g) and 0.0500 M HI (g) what is the equilibrium concentratio
n of HI?
1 answer:
Here's The Answer: <span> K = 50.2 = (2x)^2 / (0.1-x)^2
x = 0.078
so H2 eq = 0.022 M
Hope this helped! :D
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