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Aleks [24]
3 years ago
7

At 445 °C, Kc = 50.2. If one starts with 0.100 M H2 (g), 0.100 M I2 (g) and 0.0500 M HI (g) what is the equilibrium concentratio

n of HI?
Chemistry
1 answer:
garik1379 [7]3 years ago
5 0
Here's The Answer: <span> K = 50.2 = (2x)^2 / (0.1-x)^2 
x = 0.078
so H2 eq = 0.022 M

Hope this helped! :D
</span>
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How many electrons are transferred during the formation of one molecule of al2o3?
lukranit [14]
Answer:
            Six electrons are transferred in the formation of Al₂O₃.

Explanation:
                   Aluminium metal and Oxygen react to form Al₂O₃ as,

                                2 Al  +  3/2 O₂    →    Al₂O₃

Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3. Means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms. 

So, two Al atoms have lost 6 electrons and 3 O atoms have gained six electrons.
4 0
3 years ago
Write a balanced equation for the decomposition reaction described, using the smallest possible integer coefficients. When ammon
MAXImum [283]

Answer:

NH₄Cl  ------> NH₃  +  HCl

Explanation:

Ammonium Chloride =(NH₄Cl

Ammonia = NH₃

Hydrochloric Acid = HCl

NH₄Cl  ------> NH₃  +  HCl

In decomposition reaction, the reactant is breaking down into smaller parts. In this case, all of the coefficients are 1. The reaction is already balanced.

7 0
1 year ago
10. Sound is characterized in how many ways?<br> A. 5<br> B. 3<br> C. 4<br> D. None of the above
Elodia [21]

Answer:

A . 5...................

8 0
2 years ago
Read 2 more answers
A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

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3 years ago
If a reaction has an equilibrium constant slightly greater than 1, what type of reaction is it?
Paha777 [63]
Reversible, flavoring products
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